VaibhavAgarwala's blog

By VaibhavAgarwala, history, 7 weeks ago, In English

I have polygon and its vertices represented with randomly shuffled 2d points, how can I find the correct order?

In correct order I mean order so that segment between P[i] and P[(i + 1) % n] is a side of polygon.

Or if this is hard, how to solve it for 4 sides?

I'm looking for an efficient solutions. Many thanks.

 
 
 
 
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7 weeks ago, # |
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You can find the upper hull of the points, add it to the list, then add the points sorted by their x coordinates (lower points first)

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    7 weeks ago, # ^ |
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    Simple and useful.

    I actually used comparator based on this idea, didn't split the points

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7 weeks ago, # |
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Is the polygon guaranteed to be convex?

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    7 weeks ago, # ^ |
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    It's not stated anywhere, so I assume not. It will also be a very obvious / known question in that case.

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      6 weeks ago, # ^ |
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      why are people downvoting this? I answered the question in another comment and the author of the blog seemed fine with it. The convex case would just be finding a convex hull, and there are many known algorithms for that

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        6 weeks ago, # ^ |
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        If you are given a set of points in $$$R^2$$$, then there isn't a unique way of making a non-convex polygon out of them. Take for example the points $$$(1,0),(0,1),(-1,0),(0,-1),(0,0)$$$. There are 4 natural ways you could make a non-convex polygon out of them.

        Only when you assume the points should form a convex polygon will the answer be unique.

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          6 weeks ago, # ^ |
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          of course it wouldn't be unique, but we can't make assumptions to make our life simpler. and also a convex polygon of n vertices can have 2n orders :/ (rotation, flip)

          That said, I understand why there's the confusion, but my answer seemed to satisfy VaibhavAgarwala, so I guess he meant any order (correct me if I'm wrong)

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6 weeks ago, # |
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wouldn't it be the right thing to do,to simply sort them in clockwise direction, using the formula of cos between 2 vectors,however,you have to fing the center of that polygon to form the vectors