OmaeWaMouShenDeiru's blog

little math problem :D

By OmaeWaMouShenDeiru, 9 years ago, In English

hey guys :D

I have this small math problem,

( a * b ) mod n = 1

Given a, n:

find the smallest value of 'b' that satisfies the equation above.

any Idea about how to find the answer better than linear time search.

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9 years ago, # |
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http://en.wikipedia.org/wiki/Modular_multiplicative_inverse

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    9 years ago, # ^ |
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    this is the same as finding the inverse of A (mod C) right ??

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      9 years ago, # ^ |
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      Yes, it's the same. Wikipedia article has some examples.

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    9 years ago, # ^ |
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    one more question please, who to choose the proper values for a, n

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      9 years ago, # ^ |
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      ikatanic any constraints on values other than 'a' and 'n' should be co primes ??

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        9 years ago, # ^ |
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        Nope. Extended Euclidean algorithm is used to solve the equation Ax+By=GCD(A,B) and since GCD(a,n)=1 the equation a*b-k*n=1=GCD(a,n) has infinitely many solutions.

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          9 years ago, # ^ |
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          But I found this statement on some website:

          "Only the numbers coprime to C (numbers that share no prime factors with C) have a modular inverse (mod C)"

          this is for the formula above in my post.

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          9 years ago, # ^ |
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          You are not right. GCD(a, n) must be equal to 1, otherwise it has no solution. You can read here

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            9 years ago, # ^ |
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            He knows that, I just said that there is not another constraint.

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9 years ago, # |
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(a*b) mod n = 1 means that (a*b) = k*n+1 for some integer k>=0.

a*b-k*n = 1 is an equation of the form Ax+By=C which can be solved using Extended Euclidean algorithm.

Update: When I started writing my comment I didn't see that ikatanic has commented, sorry :)

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