nikizakr's blog

By nikizakr, history, 5 weeks ago, In English,

the build function in segment tree :

void build(int id = 1,int l = 0,int r = n){
	if(r - l < 2){	//	l + 1 == r
		s[id] = a[l];
		return ;
	}
	int mid = (l+r)/2;
	build(id * 2, l, mid);
	build(id * 2 + 1, mid, r);
	s[id] = s[id * 2] + s[id * 2 + 1];
}

divide and conquer algorithm to find maximum element in array :

int Max(int s = 1 , int e = n){
      if(s == e) return arr[s] ; 
      int choice1 = arr[s] , choice2 = arr[e] ; 
      choice1 = max( choice1 , Max( s , (s + e)/2 ) ; 
      choice2 = max( choice2 , Max( (s + e)/2 + 1 , e )   ;
     return max(choice1 , choice2)  ; 
}

why the complexity of the first function is O( n * log(n) ) And the second is O(n) thanks for your help :D

 
 
 
 

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5 weeks ago, # |
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5 weeks ago, # |
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The complexity of the first algorithm is also O(n).