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Div2 518A
By yashgulani, history, 5 years ago, In English

Why double coins = (double)(k+l)/m and then ceil(coins) works

And this one faila for case 28

ll long long int main() { ll n,m,k,l; cin>>n>>m>>k>>l;

ll coins = ceil((double)(k+l)/m);

if(k+l > n || coins*m > n)
{
    cout<<"-1"<<endl;
}
else {
    cout<<coins<<endl;
}
//main();

}

Thanks in advance

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5 years ago, # |
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5 years ago, # |
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Always try to stick to integers.

In this case it's equivalent (mathematically) to ll coins = (k+l+m-1)/m;

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5 years ago, # |
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I faced the same problem. But it's working fine with long double.

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