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### zarif_2002's blog

By zarif_2002, history, 5 months ago, ,

[problem:banh-me]

what's wrong with this code? please.

# include<math.h>

int main(){

long long k,l;

int a,b,i,p,q,j,ara[100003],t;

long long r,s1;

char s[100003];

l = pow(10,9) + 7;

scanf("%d %d\n",&a,&b);

gets(s);

t = 0;

for(i = 0; i < a; i++){

if(s[i] == '1'){

t++;
}
ara[i + 1] = t;
}
for(i = 0; i < b; i++){

scanf("%d %d",&p,&q);

s1 = ara[q] - ara[p - 1];

r = ((long long)q - (long long)p + 1) - s1;

k = pow(2,r)*((pow(2,s1)) - 1);

k = k%l;

printf("%lld\n",k);
}
return 0;

}

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 » 5 months ago, # |   0 You have to make your own power function , Since pow() will fail at larger number...
 » 5 months ago, # |   0 As the power of 2 can be very large (10^5) in this problem, you can't contain it any classical data type. And we only need the power of 2 in this problem, you can store the powers by simply running a loop. const long long mod=1000000007; long long pwr[100007]; pwr[0]=1; for(int i=1;i<100002;i++)pwr[i]=(pwr[i-1]*(long long)2)%mod; But you should learn about bigmod to find large power of a number.As, the pow function actually returns a double value, it is wise not use pow function.