### DoNtTellMeWhatToDo's blog

By DoNtTellMeWhatToDo, 7 days ago, ,

Can someone share the results, please?

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 » 7 days ago, # |   0
•  » » 7 days ago, # ^ |   -12 Призëр?
 » 7 days ago, # |   0 can anyone open the link given in the pic?!
 » 7 days ago, # |   +1
 » 6 days ago, # |   0 There are more participants in the CMS ranking but less in the official site. Which of them will be considered while dividing medals?
•  » » 6 days ago, # ^ |   0 In CMS rating is all participant (official and non-official), while official site count only official participants. Medal will be given to official ones
•  » » » 6 days ago, # ^ |   0 Do they follow the general rule? I mean dividing like 1/12 gold, 1/6 silver, and 1/4 bronze medals.
•  » » » » 6 days ago, # ^ |   +3 I think no
 » 6 days ago, # |   +11 What is the official solution for E? I solved it onsite with dp and lazy segtree, but the number of solves confused me (in our team's opinion there were easier problems that were solved less), so I wonder if there is an easier solution.
•  » » 6 days ago, # ^ |   +5 Convert the problem to the following dp:DP[position][answer] — maximum position j, such that the last jump was the interval [j; position] and the number of jumps was answer.To get we will have the obvious transition from DP[pos] to DP[pos+1] (the values can stay the same) and we also will have additional transitions. We will just binary search on partial sums to find the closest position to the right, such that we can jump to it and increase the answer in the state. This way we have O(N) transitions for each position.We can easily make the state have O(N) by not keeping the position. Now the only last observation is that we only need to consider the largest/last 2 values in the dp and do binary search for them only. This way we get solution.
•  » » 6 days ago, # ^ |   +6 hint1pref[i] - pref[j] >= pref[j] - pref[k] => pref[i] >= 2 * pref[j] - pref[k]2 * pref[j] - pref[k] is constant for every j hint2dp[i] >= dp[i - 1] hint3we should do things like in convex hull ;2 * pref[i] - pref[j] is like intersection , dp[i] is like kP.S sorry for my poor English