### atlasworld's blog

By atlasworld, history, 3 years ago,

Hello! We are given an integer N, The set [1,2,3,…,N] contains a total of N! unique permutations.

By listing and labeling all of the permutations in order, We get the following sequence (ie, for n = 3 ) :

1. "123"
2. "132"
3. "213"
4. "231"
5. "312"
6. "321"

Given n and k, return the kth permutation sequence.

For example, given n = 3, k = 4, ans = "231"

if n = 11, k = 1, ans = "1234567891011"

In this case, k will be a positive integer that is less than INT_MAX. n is reasonable enough to make sure the answer does not bloat up a lot.

N can be upto 1000 , k can be upto 1000.

How to solve it, simple backtracking will time out after N>10.

• -12

 » 3 years ago, # |   0
•  » » 3 years ago, # ^ |   0 but when we concatenate 10 and 11 it will be 1011 i.e 1,0,1,1. how to do for numbers?
•  » » » 3 years ago, # ^ | ← Rev. 2 →   0 Apply the algorithm for a vector not string.
•  » » » » 3 years ago, # ^ |   0 ok! i understand. I will apply. Thanks for help!