I need help to solved this intersting problem link .
thank you in advance.
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if you now know how to solve it then please help .
not sure at all but this might work:
First, let's work on finding the # of cool numbers <= X, for a given X (then we can get the answer by computing that for B and A-1).
For a fixed X, we can get the # of cool numbers with a dp[digit][sum1][sum2][alreadyless_bit]
digit will be the position of the digit we're trying, We will go from most significative to least. sum1 and sum2 are the sums of the two sets. alreadyless_bit tells if we are already strictly less than X, if so, the new digit can be any digit, otherwise, it has to be between 0 and the respective X's digit.
This counts the cool numbers but it might count each one many times, I don't know if you can avoid that hehe
Did you solve this problem later.. ? If yes can you share your idea?
Can someone help in this question
I might be wrong, but how about...
...submitting some "solutions" close to the source size limit? ;)
I couldn't think of any solution. I know above idea proposed by lmn0x4F seems to be good but couldn't find a way to for overcounting issue.
Can you provide some hint?
I viciously precomputed answers for blocks of size 200000 and then solved naively for the remainders. You might want to have a fast naive solver (i.e., $$$O(d)$$$ instead of $$$O(d^2)$$$ knapsack). Keep in mind the 50K source size limit.
Thanks a lot for sharing your approach