这可以说是一道数论(? 首先可以发现$x$的取值为$[0,min(a,S/n)]$,$$$y$$$的取值为$$$S-xn$$$ $$$x$$$的取值最大为$$$min(a,S/n)$$$,得$$$y$$$的取值为$$$S-min(a,S/n)n$$$ 只要判断$y$是否小于等于$b$就好了
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这可以说是一道数论(? 首先可以发现$x$的取值为$[0,min(a,S/n)]$,$$$y$$$的取值为$$$S-xn$$$ $$$x$$$的取值最大为$$$min(a,S/n)$$$,得$$$y$$$的取值为$$$S-min(a,S/n)n$$$ 只要判断$y$是否小于等于$b$就好了
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Google Translate says:
"This can be said to be a number theory (? First, we can find that the value of $$$ x $$$ is $$$ [0, min (a, S / n)] $$$, and the value of y is S−xn. The maximum value of x is min (a , S / n), the value of y is S−min (a, S / n) n Just judge whether $$$ y $$$ is less than or equal to $$$ b $$$"