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An O(n^2) solution gave me TLE on test 10. I came across one of the solutions below.

main() {

int n,i,f,s;
 cin>>n;
 map<int,int> mp;
 pair<int , int> a[n];
 for(i=0;i<n;i++)
 {
    cin>>f>>s;
    mp[f]++;
    a[i]={f,s};
 }

int m=n-1;
for(i=0;i<n;i++)
{
    a[i].first=m+mp[a[i].second];
    a[i].second=m-mp[a[i].second];

    cout<<a[i].first<<" "<<a[i].second<<endl;
}

}

I don't understand how the following two lines work.

a[i].first=m+mp[a[i].second];

a[i].second=m-mp[a[i].second];

Each team plays n-1 home and n-1 away games . But what is purpose of mp[a[i].second]? Please help.