Given a range [l r] find the sum of last digits of fibonacci numbers between l and r. i.e , last(fib(l))+last(fib(l+1)) .... last(fib(r)),
where last(fib(a)) denotes last digit of ath fibonacci number.
1<=l<=r<=1e9
# | User | Rating |
---|---|---|
1 | ecnerwala | 3649 |
2 | Benq | 3581 |
3 | orzdevinwang | 3570 |
4 | Geothermal | 3569 |
4 | cnnfls_csy | 3569 |
6 | tourist | 3565 |
7 | maroonrk | 3531 |
8 | Radewoosh | 3521 |
9 | Um_nik | 3482 |
10 | jiangly | 3468 |
# | User | Contrib. |
---|---|---|
1 | maomao90 | 174 |
2 | awoo | 164 |
3 | adamant | 162 |
4 | TheScrasse | 159 |
5 | nor | 158 |
6 | maroonrk | 156 |
7 | -is-this-fft- | 151 |
8 | SecondThread | 147 |
9 | orz | 146 |
10 | pajenegod | 145 |
Given a range [l r] find the sum of last digits of fibonacci numbers between l and r. i.e , last(fib(l))+last(fib(l+1)) .... last(fib(r)),
where last(fib(a)) denotes last digit of ath fibonacci number.
1<=l<=r<=1e9
Name |
---|
Using Pisano Period for $$$base = 10$$$ then we have $$$\pi(n) = 60$$$ numbers per cycle