So Which game are you going to play tourist on your brand new Play Station 5?

Crossing my fingers that "we value skills like high-performance coding" doesn't mean "Anyone who uses java is going to have a concussion from banging their head against their desk because of how tight we made these time limits"

The more different rounds, the better! I also really hope that the tasks will be good.

Nice T-shirt :)

"Throughout the year, once per quarter, we will be inviting you to join DELTIX rounds at Codeforces." Wait, so we're gonna have one of these every 3ish months? :O

I would love to have that PS5.But I won't be able to achieve that this time.Maybe 5-6 years later in some div1 + div2 I will get PS6!!!

Best of luck to all the participants :)

Warning: This round will be slightly harder, because I will be on a plane instead of donating my rating.

Please make the pretests strong! That's all I ask.

Woah 8 problems? This one is big.

Nowadays codeforces is giving a lot of gap between two contests

Nice prizes !! Hope to win one of them in the future :))

8 problems in 2 hour and 15 minutes... are we going to face some easy questions!

Me being a 'specialist' calculating my probability of winning a PS5 in a combined round. But I forgot I'm bad at probabilities and even CP (-_-)

Can I have a T-shirts from the random generator :)))

Throughout the year, once per quarter, we will be inviting you to join DELTIX rounds at Codeforces.

I'm excited to see that! Woahh, more div.1 + div.2 means more participating for me

Time for SpeedForces.

when you know there are playstation 5! you must be ready for the contest

I feel a little envious about the top three.

I'm very excited for this one, since it's happening after a long time. All the best everyone.

to all testers whose list will appear very soon

Testers were probably excited to put their feedback comments. Don't delay it further.

I already knew that the PS5 is going to be one of LGM's. :)

Hope Bugaboos will be good. May random be on my favor (that doesn't mean i want t-shirts :p)

how many bugaboos?

As a tester, I can assure the problem set is fun, well atleast the first half surely is. Good luck!

Good Luck everyone for this round!!!

We have four purple questionsetters!

Where is Anton when you need him?

kindly don't put a super hard and unconventional div2 B problem.

The winner of the contest will be probably have no time to play PS5 otherwise he wouldn't be the winner in first place :D

what about scoring distribution? Also as a contributor i want some testing.

Is it rated???

:)

everyone talking about prizes, I'm thinking to become candidate master asap.

is it impossible to improve in codeforces without watching anime ?

hoping this will not be a div 1.5 round !

Score distribution looks sus

Can someone clarify that will it be rated for Div. 2 participants or not?

is it going to be a difficult or moderate one looking at the scoring distributions

Codeforces is broken on my PC but it's working fine on mobile. Is it only happening to me?

It will be my first contest as a specialist. Hoping for the best.

deltix round == bad round

Looking at the standings, it seems Tourist is in urgent need of another PS5 ! Oh by the way, is there going to be Bugatorial for this round?

What's wrong with B??

And i thought the contest will be easy since it has 8 questions.LOL!!!!!!!!!

I really wish an easier problem was in place of D. Instead of writing this comment, I would have been solving a problem that was actually in my league. Contest would have been more enjoyable :(

Out of > 18 000 registered participants only 8 700 submitted anything after 90 minutes.

speedforces

D is too tough to even try

statement of C is shit

Please, help understand problem E

this bruteforce solution gives wa on 2-nd and 3-rd samples

void go(string s, const int m, const int k, ll &sum , ll &cnt) {
    const int n = size(s);
    int cur = 0;
    for(int l=0,r=0; l<n; ++l) {
        while(r<n && r-l<k) {
            cur += s[r] == '1';
            ++r;
        }
        if(cur > 1) {
            cnt+=1;
            sum+=m;
            return ;
        }
        cur-= s[l] == '1';
    }
    
    for(int i=0;i<n;++i) if(s[i] == '0') {
        s[i] = '1';
        go(s, m+1, k, sum, cnt);
        s[i] = '0';
    }
}


void do_test(int test){
    ii(n,k)
    
    
    ll sum = 0, cnt = 0;
    go(string(n,'0'), 0, k, sum, cnt);
    
    rr(sum, cnt)
    
    cout << sum / mint(cnt) << endl;
    
}

Problem statements should have been more clearer.(also no need of that image in each ques) :(

Oh wow! Not only bugaboos were great, but also these beautiful pictures in every bugaboo! Awesome contest.

how to solve the problem D ?

Thanks for the interesting problems!

Ok C is the worst problem I have ever seen. I spent about 40 minutes staring at it and I didn't understand the statement till now. How could this problem even got accepted by coordinators?

Apart from that the problems were great but this really ruined the contest for me.

Such a lousy statement on Problem C, it's a shame. Incomprehensible what this is about. The setters work hard to develop and work out great problems, and then ruin the result with an incomprehensible statement text. Why? I do not get it.

wasn't able to understand what the task C meant till end of the contest ;(

Pun Intended, tourist give me your old play station. :)

Am I the only stupid one who write about 100 lines for C and get 6 was??? It feels terrible (especially I notice other people in the same room pass this bugaboo neat and quickly :(

My strategy after struggling for hours with C..

Just relax in the forthcoming Deltix Rounds. Peace.

could someone provide counter case for this submission of problem c. Got 6 WA on this problem.

I hate combined rounds! I was sure that I would be able to hack a few people in D because my solution was randomized and usually, there are people who still don't seed their random number generators. However, because the round was combined and the room was mostly greens or cyans, there were only two solutions in my room, one of which had good random and the other didn't seem to have random at all.

I reduced problem D into a bipartite graph problem where friends would be in one side and currencies would be in another side. Now, if we select x from friends and y from currencies, we need all x's to be connected with all y's and we gonna take maximum y such that x meets sufficient conditions.
Couldn't proceed further.

how will you know who will be included in the list of 100 random people who will receive t-shirts?

I'm so nervous that my D will get TLE. I just use something like bruteforce....

Fine, finally a reading comprehension round.