We can solve the maximum (AND) subsequence of an array by checking the common bits in numbers in O(nlogn).But how can we find a susequence with maximum XOR?
# | User | Rating |
---|---|---|
1 | jiangly | 3640 |
2 | Benq | 3593 |
3 | tourist | 3572 |
4 | orzdevinwang | 3561 |
5 | cnnfls_csy | 3539 |
6 | ecnerwala | 3534 |
7 | Radewoosh | 3532 |
8 | gyh20 | 3447 |
9 | Rebelz | 3409 |
10 | Geothermal | 3408 |
# | User | Contrib. |
---|---|---|
1 | maomao90 | 173 |
2 | adamant | 164 |
3 | awoo | 161 |
4 | TheScrasse | 160 |
5 | nor | 159 |
6 | maroonrk | 156 |
7 | SecondThread | 152 |
8 | pajenegod | 146 |
9 | BledDest | 144 |
10 | Um_nik | 143 |
We can solve the maximum (AND) subsequence of an array by checking the common bits in numbers in O(nlogn).But how can we find a susequence with maximum XOR?
hello everyone,
Recently i came across this problem http://www.spoj.com/problems/DQUERY/en/. I coded the offline solution, but i was wondering how to solve it using persisent segment trees.I kept an array last_occur[i] which stores the latest occurence of the number i. now given a range (l,r) we need to find number of distinct elements with last_occur[i] < l.I got stuck here, how do we solve this part?
Name |
---|