Package for this problem was not updated by the problem writer or Codeforces administration after we’ve upgraded the judging servers. To adjust the time limit constraint, solution execution time will be multiplied by 2. For example, if your solution works for 400 ms on judging servers, then value 800 ms will be displayed and used to determine the verdict.

Virtual contest is a way to take part in past contest, as close as possible to participation on time. It is supported only ACM-ICPC mode for virtual contests.
If you've seen these problems, a virtual contest is not for you - solve these problems in the archive.
If you just want to solve some problem from a contest, a virtual contest is not for you - solve this problem in the archive.
Never use someone else's code, read the tutorials or communicate with other person during a virtual contest.

No tag edit access

I. Luck is in Numbers

time limit per test

1 secondmemory limit per test

256 megabytesinput

input.txtoutput

output.txtVasya has been collecting transport tickets for quite a while now. His collection contains several thousands of tram, trolleybus and bus tickets. Vasya is already fed up with the traditional definition of what a lucky ticket is. Thus, he's looking for new perspectives on that. Besides, Vasya cannot understand why all tickets are only divided into lucky and unlucky ones. He thinks that all tickets are lucky but in different degrees. Having given the matter some thought, Vasya worked out the definition of a ticket's degree of luckiness. Let a ticket consist of 2*n* digits. Let's regard each digit as written as is shown on the picture:

You have seen such digits on electronic clocks: seven segments are used to show digits. Each segment can either be colored or not. The colored segments form a digit. Vasya regards the digits as written in this very way and takes the right half of the ticket and puts it one the left one, so that the first digit coincides with the *n* + 1-th one, the second digit coincides with the *n* + 2-th one, ..., the *n*-th digit coincides with the 2*n*-th one. For each pair of digits, put one on another, he counts the number of segments colored in both digits and summarizes the resulting numbers. The resulting value is called the degree of luckiness of a ticket. For example, the degree of luckiness of ticket 03 equals four and the degree of luckiness of ticket 2345 equals six.

You are given the number of a ticket containing 2*n* digits. Your task is to find among the tickets whose number exceeds the number of this ticket but also consists of 2*n* digits such ticket, whose degree of luckiness exceeds the degrees of luckiness of the given ticket. Moreover, if there are several such tickets, you should only choose the one with the smallest number.

Input

The first line contains the number of the ticket that consists of *k* characters (*k* = 2*n*, 1 ≤ *n* ≤ 10^{5}).

Output

Print the number of the sought ticket or "-1" (without the quotes) if no such ticket exists.

Examples

Input

13

Output

20

Input

2345

Output

2348

Input

88

Output

-1

Codeforces (c) Copyright 2010-2017 Mike Mirzayanov

The only programming contests Web 2.0 platform

Server time: Jul/28/2017 09:43:59 (c2).

Desktop version, switch to mobile version.

User lists

Name |
---|