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E. Little Elephant and Strings

time limit per test

3 secondsmemory limit per test

256 megabytesinput

standard inputoutput

standard outputThe Little Elephant loves strings very much.

He has an array *a* from *n* strings, consisting of lowercase English letters. Let's number the elements of the array from 1 to *n*, then let's denote the element number *i* as *a*_{i}. For each string *a*_{i} (1 ≤ *i* ≤ *n*) the Little Elephant wants to find the number of pairs of integers *l* and *r* (1 ≤ *l* ≤ *r* ≤ |*a*_{i}|) such that substring *a*_{i}[*l*... *r*] is a substring to at least *k* strings from array *a* (including the *i*-th string).

Help the Little Elephant solve this problem.

If you are not familiar with the basic notation in string problems, you can find the corresponding definitions in the notes.

Input

The first line contains two space-separated integers — *n* and *k* (1 ≤ *n*, *k* ≤ 10^{5}). Next *n* lines contain array *a*. The *i*-th line contains a non-empty string *a*_{i}, consisting of lowercase English letter. The total length of all strings *a*_{i} does not exceed 10^{5}.

Output

On a single line print *n* space-separated integers — the *i*-th number is the answer for string *a*_{i}.

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

3 1

abc

a

ab

Output

6 1 3

Input

7 4

rubik

furik

abab

baba

aaabbbababa

abababababa

zero

Output

1 0 9 9 21 30 0

Note

Let's assume that you are given string *a* = *a*_{1}*a*_{2}... *a*_{|a|}, then let's denote the string's length as |*a*| and the string's *i*-th character as *a*_{i}.

A substring *a*[*l*... *r*] (1 ≤ *l* ≤ *r* ≤ |*a*|) of string *a* is string *a*_{l}*a*_{l + 1}... *a*_{r}.

String *a* is a substring of string *b*, if there exists such pair of integers *l* and *r* (1 ≤ *l* ≤ *r* ≤ |*b*|), that *b*[*l*... *r*] = *a*.

Codeforces (c) Copyright 2010-2019 Mike Mirzayanov

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