No tag edit access

C. Two permutations

time limit per test

6 secondsmemory limit per test

512 megabytesinput

standard inputoutput

standard outputYou are given two permutations *p* and *q*, consisting of *n* elements, and *m* queries of the form: *l*_{1}, *r*_{1}, *l*_{2}, *r*_{2} (*l*_{1} ≤ *r*_{1}; *l*_{2} ≤ *r*_{2}). The response for the query is the number of such integers from 1 to *n*, that their position in the first permutation is in segment [*l*_{1}, *r*_{1}] (borders included), and position in the second permutation is in segment [*l*_{2}, *r*_{2}] (borders included too).

A permutation of *n* elements is the sequence of *n* distinct integers, each not less than 1 and not greater than *n*.

Position of number *v* (1 ≤ *v* ≤ *n*) in permutation *g*_{1}, *g*_{2}, ..., *g*_{n} is such number *i*, that *g*_{i} = *v*.

Input

The first line contains one integer *n* (1 ≤ *n* ≤ 10^{6}), the number of elements in both permutations. The following line contains *n* integers, separated with spaces: *p*_{1}, *p*_{2}, ..., *p*_{n} (1 ≤ *p*_{i} ≤ *n*). These are elements of the first permutation. The next line contains the second permutation *q*_{1}, *q*_{2}, ..., *q*_{n} in same format.

The following line contains an integer *m* (1 ≤ *m* ≤ 2·10^{5}), that is the number of queries.

The following *m* lines contain descriptions of queries one in a line. The description of the *i*-th query consists of four integers: *a*, *b*, *c*, *d* (1 ≤ *a*, *b*, *c*, *d* ≤ *n*). Query parameters *l*_{1}, *r*_{1}, *l*_{2}, *r*_{2} are obtained from the numbers *a*, *b*, *c*, *d* using the following algorithm:

- Introduce variable
*x*. If it is the first query, then the variable equals 0, else it equals the response for the previous query plus one. - Introduce function
*f*(*z*) = ((*z*- 1 +*x*)*mod**n*) + 1. - Suppose
*l*_{1}=*min*(*f*(*a*),*f*(*b*)),*r*_{1}=*max*(*f*(*a*),*f*(*b*)),*l*_{2}=*min*(*f*(*c*),*f*(*d*)),*r*_{2}=*max*(*f*(*c*),*f*(*d*)).

Output

Print a response for each query in a separate line.

Examples

Input

3

3 1 2

3 2 1

1

1 2 3 3

Output

1

Input

4

4 3 2 1

2 3 4 1

3

1 2 3 4

1 3 2 1

1 4 2 3

Output

1

1

2

Codeforces (c) Copyright 2010-2018 Mike Mirzayanov

The only programming contests Web 2.0 platform

Server time: Mar/19/2018 02:25:49 (d2).

Desktop version, switch to mobile version.

User lists

Name |
---|