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F. Ordering T-Shirts

time limit per test

2 secondsmemory limit per test

256 megabytesinput

standard inputoutput

standard outputIt's another Start[c]up, and that means there are T-shirts to order. In order to make sure T-shirts are shipped as soon as possible, we've decided that this year we're going to order all of the necessary T-shirts before the actual competition. The top *C* contestants are going to be awarded T-shirts, but we obviously don't know which contestants that will be. The plan is to get the T-Shirt sizes of all contestants before the actual competition, and then order enough T-shirts so that no matter who is in the top *C* we'll have T-shirts available in order to award them.

In order to get the T-shirt sizes of the contestants, we will send out a survey. The survey will allow contestants to either specify a single desired T-shirt size, or two adjacent T-shirt sizes. If a contestant specifies two sizes, it means that they can be awarded either size.

As you can probably tell, this plan could require ordering a lot of unnecessary T-shirts. We'd like your help to determine the minimum number of T-shirts we'll need to order to ensure that we'll be able to award T-shirts no matter the outcome of the competition.

Input

Input will begin with two integers *N* and *C* (1 ≤ *N* ≤ 2·10^{5}, 1 ≤ *C*), the number of T-shirt sizes and number of T-shirts to be awarded, respectively.

Following this is a line with 2·*N* - 1 integers, *s*_{1} through *s*_{2·N - 1} (0 ≤ *s*_{i} ≤ 10^{8}). For odd *i*, *s*_{i} indicates the number of contestants desiring T-shirt size ((*i* + 1) / 2). For even *i*, *s*_{i} indicates the number of contestants okay receiving either of T-shirt sizes (*i* / 2) and (*i* / 2 + 1). *C* will not exceed the total number of contestants.

Output

Print the minimum number of T-shirts we need to buy.

Examples

Input

2 200

100 250 100

Output

200

Input

4 160

88 69 62 29 58 52 44

Output

314

Note

In the first example, we can buy 100 of each size.

Codeforces (c) Copyright 2010-2018 Mike Mirzayanov

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