time limit per test: 0.75 sec. memory limit per test: 4096 KB
input: standard output: standard
There is a row consist of N coins. Each coin lies heads up or tails up. There is also binary vector A with (K-1) dimensions. We accomplish M operations with our coins row: we select some consecutive K coins, and apply to selected coins transformation X for Di times (i=1..M, where i is a number of operation) The transformation X for given row C with length K means: 1. We shift the row C in one position to the left in a cyclic way. 2. Then we scan the row C from the first (leftmost) coin to (K-1)-th coin: if coin Ci lies tails up, and Ai=1, then we turn over coin Ck Obviously, that for constant coins row with length K transformation X is fully determined by vector A. But vector A haven't given to you. You have results of transformation L rows with length K (row of coins before transformation, and row after transformation). It is guarantied that there is exactly one vector A satisfied all L conditions. Your task is to reconstruct initial row by given row after all operations being accomplished.
There is four integer numbers in the first line of input: N, M, K, L (2<=N<=50, 1<=M<=10, 1<=L<=200, 2<=K<=N). Second line contains description of accomplished operations, M pairs of positive integer numbers Si and Di. Si is a starting point of selected coins subrow, Di is a number of iterations of transformation (Si <= N-K+1; Di <= 10^6). There are the following L conditions determining transformation X, L blocks by two lines each: first line of each block contains a row before transformation, and the second line contains row after transformation. Each line consists of K symbols, 1 denotes tails, 0 denotes heads. The last line contains N symbols - row of coins after all operations accomplished. i-th symbol is 1 if i-th coin lies tails up, and 0 otherwise.
Write N symbols in single line of output: i-th symbol must be 1 if i-th coin of initial row laid tails up, and 0 otherwise.
4 2 3 2 2 1 1 1 010 101 101 011 1010
Saratov ST team Spring Contest #1
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