Can anybody please explain me the following part of this Solution:- int t = H[h][l].second ^ H[h][r].second; bool ok = t — (t & -t); if(!ok) printf("Yes\n"); else printf("No\n");
Problem 570-D
Can anybody please explain me the following part of this Solution:- int t = H[h][l].second ^ H[h][r].second; bool ok = t — (t & -t); if(!ok) printf("Yes\n"); else printf("No\n");