Calculating (C(k, k) + C(k+1, k) + C(k+2, k) + ... + C(m, k)) modulo 1234567890 (m >= k) in 1 second?

Revision en1, by xuanquang1999, 2016-08-16 15:48:48

Is there a way to do this?

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  Rev. Lang. By When Δ Comment
en2 English xuanquang1999 2016-08-16 15:52:00 55 Tiny change: 'to do this?' -> 'to do this if m, k <= 10^9?\n\nPS: C here mean combination number.'
en1 English xuanquang1999 2016-08-16 15:48:48 127 Initial revision (published)