Is there any formula for calculating the count of prime factors of a number 'N'? I know the loose upper bound is log2(N) but is there a better upper bound? Thanks.
Formula for count of prime factors of a number
Is there any formula for calculating the count of prime factors of a number 'N'? I know the loose upper bound is log2(N) but is there a better upper bound? Thanks.
Rev. | Язык | Кто | Когда | Δ | Комментарий | |
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en1 | rogerfederer07 | 2021-06-24 11:37:14 | 209 | Initial revision (published) |