SGU-151

Exactly the same code, GNU C++11 got WA on test #19 75830647, GNU C++14 got AC 75830595. I submitted 30 times to find the problem.

#include <cstdio>
#include <cmath>
static const double EPS = 1e-13;
int main() {
    double c, b, m; scanf("%lf%lf%lf", &c, &b, &m);
    double c2 = c * c, b2 = b * b, m2 = m * m;
    double a2 = 2 * (b2 + c2) - 4 * m2;
    if (a2 < 0) {
        printf("Mission impossible");
        return 0;
    }
    double a = sqrt(a2);
    if ((a + b < c) || (a + c < b) || (b + c < a)) {
        printf("Mission impossible");
        return 0;
    }
    double x = (c2 - b2) / (2 * a);
    if (fabs(a) < EPS) x = 0;
    double y = sqrt(m2 - x * x);
    printf("%.5lf %.5lf\n",x,y);
    printf("%.5lf %.5lf\n",-(a)/(double)2.0,(double)0);
    printf("%.5lf %.5lf",(a)/(double)2.0,(double)0);
    return 0;
}

I hope the Codeforces maintainers verify the test data and my report of SGU-124

SGU-124

I solve this problem by counting the number of intersections of the closed broken line and ray from (x0,y0+0.5) to left, but got WA on test case #15. Then I changed the ray from (x0, y0+0.5) to right, and got AC.

I performed a sanity check on the test data, and the test passed first 14 test cases but failed on #15: the closed broken line is without self-crossings and self-contacts, so every endpoints appears exactly twice in the broken line.

I hope the Codeforces maintainers verify the test data.

Hello, I made a very classic tree problem. I want to get some clean solutions, because my solution seems very complicated. I made this problem on Polygon, but cannot make it public to every one. So I publish this problem here.

I hope you can give me good solutions (maybe by ideone.com / or join my group).

I create a group called "problem sharing" at http://codeforces.com/group/t0m8sIZmgT. You can join this group to solve this problem.

5 2
1 3 4 2 5
1 2
2 3
3 4
4 5

4 2 5 3 4 

5 2
1 3 7 2 5
1 5
2 5
3 5
4 5

7 7 3 7 -1