WTF, lol, How is this problem 2000 difficulty? https://codeforces.com/problemset/problem/1919/H
№ | Пользователь | Рейтинг |
---|---|---|
1 | ecnerwala | 3650 |
2 | Benq | 3582 |
3 | Geothermal | 3570 |
3 | orzdevinwang | 3570 |
5 | cnnfls_csy | 3569 |
6 | tourist | 3565 |
7 | maroonrk | 3532 |
8 | Radewoosh | 3522 |
9 | Um_nik | 3483 |
10 | jiangly | 3468 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | maomao90 | 174 |
2 | awoo | 164 |
3 | adamant | 163 |
4 | TheScrasse | 159 |
5 | nor | 158 |
6 | maroonrk | 156 |
7 | -is-this-fft- | 151 |
8 | SecondThread | 147 |
9 | orz | 146 |
10 | pajenegod | 145 |
WTF, lol, How is this problem 2000 difficulty? https://codeforces.com/problemset/problem/1919/H
Let $$$m$$$ be some positive integer (not necessary prime) . There is a way to calculate $$$\displaystyle{\frac{a}{b}}\%m$$$ when b is not very big and $$$a \% b = 0$$$ Firstly, let's notice, that $$$\displaystyle{\frac{a}{b}}=mk+(a/b)\%m$$$, for some integer value k. Now, let's do some mathematical stuff:
So, the answer is $$$(a\%mb)/b$$$
Hi Guys, Can anyone help me solve this problem?
https://acm.timus.ru/problem.aspx?space=1&num=2019&locale=en
I tried to solve it greedily. Also i tried to solve it using dynamic programming. I had dp[l][r] true if exists k such that dp[l][k] is true and dp[k + 1][r] is true or dp[l + k][r — k] is true and we can connect letters from range (l, l + k) to the letters from range (r — k, r). Unfortunately, that works for O(n^3)
Название |
---|