flamestorm's blog

By flamestorm, 12 months ago, In English

Hello, Codeforces!

I, along with AlperenT, Ari, BucketPotato, ScarletS, and ToxicPie9, would like to invite everyone on Codeforces to the April Fools Day Contest 2023! The 11th April Fools Day Contest will take place on Apr/01/2023 17:35 (Moscow time). This is a joke competition in which solving the problem is often easier than figuring out what the actual task is.

Please note that the round is unrated.

In this round you'll be given $$$n$$$ weird problems and 2 hours to solve them, where $$$7 \leq n \leq 12$$$. At most $$$\sqrt{n}$$$ of the problems will be interactive. The contest will use ACM ICPC rules (no hacks, the standings are decided by the number of solved problems and penalty time earned on them).

You can submit solutions in any language allowed by Codeforces, unless the problem says otherwise. To get an idea of what the contest will look like, you can check out the contests of the past years: 2012, 2013, 2014, 2016, 2017, 2018, 2019, 2020, 2021, 2022.

Good luck, and have fun!

UPD1: Thanks willy108 for testing!

UPD2: The editorial is released!

UPD3: Congrats to the winners!

  1. InternetPerson10
  2. Geothermal
  3. A_G
  4. Maksim1744
  5. LJC00118

And congrats to the first solvers!

UPD4: Sorry for the inconvenience, the contest is now open for practice submissions + virtuals.

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12 months ago, # |
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As an author, give me contribution

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12 months ago, # |
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Who Tested?

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12 months ago, # |
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Make it rated

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12 months ago, # |
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My first april fool contest. Hope it would be funny

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12 months ago, # |
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Ac round 5

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12 months ago, # |
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Hoping it to be unrated like last time :)

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    12 months ago, # ^ |
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    well it's written there

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      12 months ago, # ^ |
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      I guess people didn't understand my sarcasm, explaining my joke to you :)

      Spoiler
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12 months ago, # |
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I am from Switzerland.

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Is this actually unrated or is that a prank ..?

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    12 months ago, # ^ |
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    Just join, I'm sure you will love it !

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I wish to see the foolest problems ever made in codeforces!

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    12 months ago, # ^ |
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    That's ok but how would you define the 'foolest' problem on codeforces?

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Is this rated ? Or As the April Fool it is a joke.....

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I hope this year will be even more fun and interesting than last year.

April 1st is called joke day for a reason.

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12 months ago, # |
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After waiting 1 year... :-) Is it rated?

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12 months ago, # |
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for fun ^_^

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12 months ago, # |
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Happy april fool

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I will join, have fun :)

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12 months ago, # |
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I read some of past years problems and understood none of them :/ is it normal?

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12 months ago, # |
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I would like to know whether the contest will be rated for anyone or unrated for all. Answer will be greatly appreciable. Thanks

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As a participant,give me rating.

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Is it rated ?

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12 months ago, # |
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ok, I pull up!!!

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Happy April 1st everyone!

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12 months ago, # |
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Okay, so this year I have to print willy108 :)

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    12 months ago, # ^ |
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    If the checker gets access to data about submitter, probably you would have to print do4z :-)

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Every previous years questions SHOCKED me, especially last year's first question lol

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Are the problems somehow related to the tasks in Ohio?

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Ahhh .. you should have told it's rated. And after contest, surprise!

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at the end when it's time to begin the contest you will say we make you fool there is no contest today.

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Good luck!

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It is important for all of us to know the history of April Fool . It is connected with religious sentiment of Muslim people.

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    12 months ago, # ^ |
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    I don't mean to be rude,but what has the day to do with Muslim?Anyway,It's from Western Countries.

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As a commentator, give me a contribution

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Here comes my favorite contest!

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Guys, remember: willy108 and 0-gon tested!

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Bittersweet memory of hitting a new peak rating from last year's april fools...

Actually, the awkward memory is from months later when I finally surpassed that and joked about having the sense to retire.

One year later...

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Spoiler
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Please upload the editorial as soon as possible!

Much needed

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Lol, my best performance on codeforces was in contest for fools

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Deleted

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me participating for the first time in april fool contest:

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SecondThread Please tel me you will upload screencast of the contest :D

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12 months ago, # |
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Hints: $$$\newline$$$ A: print("security") $$$\newline$$$ D: print(0) (0/2 = 0 — so we disproved the collatz hypothesis:)) $$$\newline$$$ E: print(0) (any number here) $$$\newline$$$ J: give me AC $$$\newline$$$

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    12 months ago, # ^ |
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    B -> 15,20,21 no else yes E -> print 100000 , Hell of a contest xD

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      12 months ago, # ^ |
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      why 15, 20, 21 no?

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        12 months ago, # ^ |
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        15th, 20th, and 21th contests were unrated.

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          12 months ago, # ^ |
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          I kinda figured it out, but how to know ?

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            12 months ago, # ^ |
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            look at standings of each contest and if it doesn't say rating changes then the round was unrated.

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    12 months ago, # ^ |
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    D could also be: print(negative integer)

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      12 months ago, # ^ |
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      Yes, I did print(-1)...from wikipedia

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    12 months ago, # ^ |
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    In problem D, I just printed -1. I got it after equating $$$(3*x+1)/2 = x$$$ and got $$$x=-1$$$.

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wtf how to solve F? I tried to delete a numbers to 7,13,19 and my draft was corrupted

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How F QAQ

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    12 months ago, # ^ |
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    Spoiler
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12 months ago, # |
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Great contest. Solved ABDEFJ.

Python code for solving F
My answer for J
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What is the solution of B? I got it by trying 40+ times (15, 20, 21 are NO, others YES) but what is the logic?

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Now contest is over. Can you please tell me what was that dammnn mysterious language!!!

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    12 months ago, # ^ |
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    ChatGPT

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    12 months ago, # ^ |
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    please

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    12 months ago, # ^ |
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    you have to use the word "pls" or "please" and then submit

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      12 months ago, # ^ |
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      and what was the logic behind entering this :)

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        12 months ago, # ^ |
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        You can look at your submission record, it will tell you to beg him for help

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        12 months ago, # ^ |
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        I asked the jury "what do you want?" to which the jury replied "wrong answer I can give you AC, but did you forget something important?", from there I remembered this comment — and added "pls" lol.

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    12 months ago, # ^ |
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    english

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    12 months ago, # ^ |
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    you had to ask judge to give you AC...

    "can you please give me AC?"

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      12 months ago, # ^ |
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      If you miss "please" then it won't give you AC. Jury was so rude >_<

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    12 months ago, # ^ |
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    In fact it's English. Submit "Please create a mysterious language." and you'll get an AC

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Zeroforces round

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Contest not for fools...

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The best round ever (with pinely round)

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How to solve C? I think it might relate to 3, 1, 4.

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Was pretty certain that J should be whitespace(even had a chuckle while submitting), but got WA, let's see what did I miss.

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    12 months ago, # ^ |
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    you had to read the jury verdict and it will say that it is a language model

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accepted please lol

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sample choice in C was genius

Spoiler to the problem
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Please!, allow the practice...
ASAP,
Thank you

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G????

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12 months ago, # |
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got trolled so hard by D

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my code for B
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Who spent several minutes trying to find long Collatz sequences for D like me? :raising_hand:

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    12 months ago, # ^ |
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    Hell yeah...

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    12 months ago, # ^ |
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    I spent 1 hour

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    12 months ago, # ^ |
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    I tried generating random 1000 digits numbers and checking whether they are greater than k... It went well for about k < 20000

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      12 months ago, # ^ |
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      $$$2^{3321} - 1$$$ needs $$$45301$$$ steps to reach $$$1$$$. That's the best I could find.

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Solution A-E

A:read the picture:security

B:note that it is "was it rated". you can find that codeforces round 1 is rated and round 15 is unrated. In the first 25 test,only round 15,20,21 are unrated.

C:t<=32 and sum of n<=155,around t*5, so you can guess that it is n is a random number between 0 to 9. As 2*1*4=8,7=7,1*2*3*5=30, you can guess that n is 31415926... and the answer is the product. the sum of the first 32 digits of pi is also actually equal to 155.

D:there is no limit of n>0.

-7 -> -20 -> -10 ->-5 -> -14 -> -7

E:the difference is 10^6 not 10^-6. if you set a=0,the condition will be always satisfied.

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    12 months ago, # ^ |
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    F : Both the given numbers have a factor if the type [(bunch of 9s) 1 (bunch of 9s)]. Check for all of them upto the number's length and find the other factor by division

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    12 months ago, # ^ |
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    There's an easier sequence for problem D 0 -> 0 -> 0....

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This was a lot of fun, thank you :)!

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    12 months ago, # ^ |
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    Hii. Could you solve the was it rate problem? I tried too many methods but I could not solve it. Can u explain me how did u solve it?

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      12 months ago, # ^ |
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      It asks whether the n-th round on Codeforces was rated. Specifically, beta rounds 15, 20 and 21 were unrated

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      12 months ago, # ^ |
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      In the first 25 rounds of codeforces's history, round 15, 20 and 21 were unrated.

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My best performance came in an April fool contest lol. Can't wait for my rating to increase. Important life lesson, I will always remember to say please to the AI overlord who is going to take over.

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What is the solution process for I?? Solution for I makes no sense to me

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    12 months ago, # ^ |
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    A person is climbing a mountain. We notice that the vertical line of the letter 'b' is upward, indicating that the person has moved up one unit. The vertical line of the letter 'p' is downward, indicating that the person has moved down one unit. Count all letters in the string that have this up-down feature. Increase the count by 1 when encountering an upward letter, and decrease it by 1 when encountering a downward letter. The initial height is 0. Output NO only when the height becomes negative at some point or the person finishes climbing the mountain (processing the entire string) with a non-zero height. Otherwise, output YES. That's my inference.

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    12 months ago, # ^ |
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    English letters have "ascenders" and "descenders": ascenders are parts of a letter that extend above a baseline, descenders parts that extend below. For example, normal letters are "a", "x" or "z", letters with ascenders are "f", "l" or "k", letters with descenders are "y", "g", "j" etc.

    So apparently the idea is that you keep track of the height and you increase by 1 when you encounter an ascender, decrease by 1 if you encounter a descender. A word is valid if you start and end at 0 without going below 0.

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12 months ago, # |
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please make it rated

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Thanks for this contest, made my day!

Also binary searching to deduce each test case for B was fun XD, later I noticed there were few "NO"s so guessed the 22nd test case but was fun lol. Most submissions I have ever made in a contest.

Spoiler
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Solution for G?

What I observed was that in the problem logo of Codeforces was given, just with all green colours. Also, if you mix red with green then you get yellow, which is first "bar" in codeforces logo. Maybe that was somehow related to input 1 R R?

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How do they got accepted for the second problem(was it rated?) without the wrong answer?

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    12 months ago, # ^ |
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    just cheating

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      12 months ago, # ^ |
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      Or maybe they correctly guessed that it was — whether the $$$n$$$ th round of Codeforces was rated or not.

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        12 months ago, # ^ |
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        correctly guessed from 2**25 possibilities?? bullshit!

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          12 months ago, # ^ |
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          You're too arrogant

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          12 months ago, # ^ |
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          No, correctly guessed from the problem statement. Calm down man. :/

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          12 months ago, # ^ |
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          actually you don't need 2^25 (and btw its 2^23 cuz there are two examples), you only need to keep doing binary searches with the 25 numbers using submissions and then you can find the other two unrated numbers.

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            12 months ago, # ^ |
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            we are talking about guessing without wrong submissions lol

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              12 months ago, # ^ |
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              Ohh didn't saw that, thanks for reminding

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    12 months ago, # ^ |
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    I went to the standings page (eg: https://codeforces.com/contest/15/standings) and checked to see if the "Rating Changes" tab was there or not.

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    12 months ago, # ^ |
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    You needed to check which of the first 25 codeforces contests were rated.

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    12 months ago, # ^ |
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    I looked at the cached versions of the announcement blogs on Google for each of the contests (blogs were disabled at the time I solved the problem) to see if the contest was rated.

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    12 months ago, # ^ |
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    I opened the first 25 contests and checked if it's rated or not

    the unrated contests of 25 contests are 15 20 21

    I solved it using the problem name it's rated?

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      12 months ago, # ^ |
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      You can open the standings table of a contest and if the rating changes option is absent, then it is unrated :D

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This was my 1st april fool contest and Really, after giving this contest , I am feeling like April fool celebrated now :-)

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When will be tutorial or live stream to this contest ? (upvote if you are interested)

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Happy to see an April Fools Day Contest with no domain knowledge such as plots or characters in a specific movie. Great contest!

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Was fun!. Guys the seco d problem called : was it rate, how someone solved it? A brief explanation if u may n.n

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    12 months ago, # ^ |
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    went to contests page, opened standings table of contests 1 to 25, then in whichever contest the friends rating changes/rating changes option is absent, that contest is unrated

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so interesting

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Is J judged by a LLM or a bunch of ifs?

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IT was a nice experience !!!

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if it is rated then it will be really a matter of danger for top coders

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Was quite frustrated with multiple wrong answers for D, but couldn't help laughing out loud when I saw the solution. XD
Great problems, keep it up! :)

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amazing! Problom J is so interesting. Did you judge it by a LLM?

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J: Please give me AC. OK,Accepted... xD

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It's very funny reading the inputs of participants for last question (Unmysterious Language).But finally it seems like we must use the word "Please" for AC

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Please do the rating update quickly and make me CM >_<

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the one who got I is a genius

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Thanks, you successfully proved I am a fool.

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12 months ago, # |
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How does the spj for D work?

Are there any conclusions that $$$\forall 1\le n \le 10^{10^3}$$$, it will finally become $$$1$$$ in less than $$$10^{18}$$$ times?(That is, all positive integers do not work)

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    12 months ago, # ^ |
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    The author set $$$k \le 142\,023$$$ ($$$1\,4\,2023$$$) to make the checker work quickly, the $$$10^{18}$$$/redacted business was intended as a bit of a red herring.

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      12 months ago, # ^ |
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      The maximum that I could generate is for $$$n = 2^{3300} - 1$$$. The sequence length is $$$45280$$$ for this number.

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        12 months ago, # ^ |
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        Collatz seems to have logarithmic length,so I doubt there is a positive integer under $$$10^3$$$ digits that has a sequence longer than $$$10^{18}$$$. The answer for the problem is a nonpositive integer.

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        12 months ago, # ^ |
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        I found $$$n = 2^{3321} - 1$$$ (during contest). The sequence has length $$$45302$$$.

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      12 months ago, # ^ |
        Vote: I like it +8 Vote: I do not like it

      https://oeis.org/A277109

      for $$$n = 2^{1812}+1$$$ , the length is $$$67108863$$$

      I submitted this number, but got Wrong Answer :(

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    12 months ago, # ^ |
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    just print 0 and boom, AC.

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12 months ago, # |
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What is the Solution of

It was rate problem?

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    12 months ago, # ^ |
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    Check first 25 contests on Codeforces which were rsted and which were not

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12 months ago, # |
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Problem G: If you download the image and check the hex code, you will get 01722b, which is the problem 1722B - Colourblindness.

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    12 months ago, # ^ |
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    Man I checked the rgb but I tunnel visioned on R=1 lol.

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12 months ago, # |
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This contest is disaster, total waste of time.

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    12 months ago, # ^ |
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    You could've seen rounds in previous years and known that they're a waste of time before actually doing it

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12 months ago, # |
Rev. 2   Vote: I like it +66 Vote: I do not like it

Thanks ChatGPT for answering questions!

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12 months ago, # |
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Why is there not a submit button???

I thought its April fool maybe haha

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12 months ago, # |
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Will upsolving be available?

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12 months ago, # |
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When can I send solutions if I can't do it virtual

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12 months ago, # |
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AMAZING. Although I didn't solve any of it, the ideas really amazed me. Furthermore, the verdict "wrong answer I can give you AC, but did you forget something important?" is interesting.

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12 months ago, # |
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The April Fools Day contest on Codeforces is awesome! It's a fun and exciting way to improve your problem-solving skills and conquer any fear you may have of the platform's difficulty. You'll be blown away by the creative and unconventional solutions to the challenging yet entertaining problems. Plus, it's a great opportunity to connect with other problem solvers from around the world. Don't miss out on this thrilling adventure!

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12 months ago, # |
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One doubt:

does plagarism check happens in April Fools Day contests?

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8 months ago, # |
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Why I can't submit my code?