int limit = 1 << n;
for (int i = 0; i < limit; i++) {
if (Integer.bitCount(i) >= 3) {
System.out.println(i);
}
}
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int limit = 1 << n;
for (int i = 0; i < limit; i++) {
if (Integer.bitCount(i) >= 3) {
System.out.println(i);
}
}
Название |
---|
There's technically no asymptotically better way. Note that the number of integers in that range that have bitCount < 3 is So the total number of integers you would be printing out is O(2n) - O(n2) = O(2n), which is at least necessary asymptotically.