Nuu's blog

By Nuu, history, 4 years ago, In English

Hi guys, Today i sees a apparently easy math problem (but i can't solved):

Two persons walk simutanious around two circles with size A and B with positions [1,2,3,...,A] and [1,2,3,...,B].

Then follow Q querys. Each query give two positions x and y, and asks the number of step for person A arrive on position x and person B arrive on position y (on same time) using O(1).

Thanks guys, i'm very novice in math problems.

 
 
 
 
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4 years ago, # |
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It asks for a question like k mod A = x and k mod B = y. This is Chinese remainder theorem application.

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4 years ago, # |
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Dear Nuu,

The equivalent Chinese Remainder problem is: Find the smallest positive integer 0 <= n <= A*B - 1 such that n mod A = x - 1 and n mod B = y - 1.

Best wishes,