VietCT's blog

By VietCT, history, 6 weeks ago, ,

Hi guys.

I have a problem want to ask you guys.

Problem: Given a tree with n nodes, m segments in a tree with 2 endpoints. Find the maximum number of segments satisfy that not exist two segments with the edge intersect. (n < 1e3, m < 1e5);

My solution (WA passed 4/5) is: Sort m segments by the depth of their LCA. If two segments have the same LCA, if one of them have the endpoint equal to their LCA i choose it ,else i choose the one have shorter length. After sorted, i pick it one by one.

My sub For example:

n = 6, m = 4;

edges:

1 2

2 3

3 4

3 5

3 6

segments:

1 3

4 5

5 6

6 4

So the answer is 2 because we can choose segment (1, 3) and segment (4, 5) as path 1 -> 3 = 1 -> 2 -> 3, path 4 — > 5 = 4 — > 3 -> 5.

You also can choose (1, 3), (5, 6) or (1, 3), (6, 4)

• 0

 » 5 weeks ago, # |   -7 Can you give link or something? Or at least explain better. Please don't expect people to understand what you mean by "Find the maximum number of segments satisfy that not exist two segments with the paths intersect."
•  » » 5 weeks ago, # ^ |   0 Sorry for my bad english i will add an example to make it more clear
•  » » 5 weeks ago, # ^ |   0 It is clear enough bro?
•  » » » 5 weeks ago, # ^ |   0 Ok, now I understand. Do you have any proof/intuition why your greedy algorithm should always produce the optimal solution? To me it is not at all clear why it should work — seems like unproven greedy.
•  » » » » 5 weeks ago, # ^ |   0 My greedy algorithm is completely wrong. You have any ideas?
•  » » » » » 5 weeks ago, # ^ |   +1 How about something like: let $\mathrm{dp}[u]$ be the most segments that can be fit completely in the subtree of $u$.