Hello Everyone, This is a just a thought that came to my mind. Normally we sort numbers with the time complexity of n log n where n is the number of numbers present in the array.Same for a list of characters. However, for a list of given strings,let us say all the strings are of equal length and that length is m. For comparing two strings we need at most iterations.So in that case , isnt the complexity (n^2)*m ???Because the recurrence relation will be T(n)=2*T(n/2)+ n*m---> where merging takes m units of time for each comparison of two strings... If anyone can clarify this doubt, It will be of great help.. Thanks in advance

If you search the title of your blog you get this StackOverflow article, which should answer your question. Took me maybe a minute to find.

Sorry,extremely sorry,should have googled it.Thanks for your kind help