Does anyone knows how to solve this problem ? http://cepc08.ii.uni.wroc.pl/cards.pdf
I've been trying to solve this problem, got some ideas but none of those ideas has really worked. Can anyone give me a hint ?
# | User | Rating |
---|---|---|
1 | ecnerwala | 3649 |
2 | Benq | 3581 |
3 | orzdevinwang | 3570 |
4 | Geothermal | 3569 |
4 | cnnfls_csy | 3569 |
6 | tourist | 3565 |
7 | maroonrk | 3531 |
8 | Radewoosh | 3521 |
9 | Um_nik | 3482 |
10 | jiangly | 3468 |
# | User | Contrib. |
---|---|---|
1 | maomao90 | 174 |
2 | awoo | 164 |
3 | adamant | 162 |
4 | TheScrasse | 159 |
5 | nor | 158 |
6 | maroonrk | 156 |
7 | -is-this-fft- | 151 |
8 | SecondThread | 147 |
9 | orz | 146 |
10 | pajenegod | 145 |
Does anyone knows how to solve this problem ? http://cepc08.ii.uni.wroc.pl/cards.pdf
I've been trying to solve this problem, got some ideas but none of those ideas has really worked. Can anyone give me a hint ?
Name |
---|
YES is when exist such k, l, n, m ≥ 0 so
c = k × a + l × b
d = m × a + n × b.
NO otherwise.
What's the proof ? I could see this approach, but I wasn't sure if this is right.
counter-example:
c=3 d=7 a=2 b=3
c=0a+1b
d=2a+1b
Yep, one more condition: a × b must divide c × d
UPD This seems to be legit, but in paper I found another: (c = q × a or d = q × a) and (c = w × b or d = w × b).
Can you prove it ?
That paper in russian. Sorry, I'm in lack of time to translate it.