To become the king of Codeforces, Kuroni has to solve the following problem.
He is given $$$n$$$ numbers $$$a_1, a_2, \dots, a_n$$$. Help Kuroni to calculate $$$\prod_{1\le i<j\le n} |a_i - a_j|$$$. As result can be very big, output it modulo $$$m$$$.
If you are not familiar with short notation, $$$\prod_{1\le i<j\le n} |a_i - a_j|$$$ is equal to $$$|a_1 - a_2|\cdot|a_1 - a_3|\cdot$$$ $$$\dots$$$ $$$\cdot|a_1 - a_n|\cdot|a_2 - a_3|\cdot|a_2 - a_4|\cdot$$$ $$$\dots$$$ $$$\cdot|a_2 - a_n| \cdot$$$ $$$\dots$$$ $$$\cdot |a_{n-1} - a_n|$$$. In other words, this is the product of $$$|a_i - a_j|$$$ for all $$$1\le i < j \le n$$$.
The first line contains two integers $$$n$$$, $$$m$$$ ($$$2\le n \le 2\cdot 10^5$$$, $$$1\le m \le 1000$$$) — number of numbers and modulo.
The second line contains $$$n$$$ integers $$$a_1, a_2, \dots, a_n$$$ ($$$0 \le a_i \le 10^9$$$).
Output the single number — $$$\prod_{1\le i<j\le n} |a_i - a_j| \bmod m$$$.
2 10 8 5
3
3 12 1 4 5
0
3 7 1 4 9
1
In the first sample, $$$|8 - 5| = 3 \equiv 3 \bmod 10$$$.
In the second sample, $$$|1 - 4|\cdot|1 - 5|\cdot|4 - 5| = 3\cdot 4 \cdot 1 = 12 \equiv 0 \bmod 12$$$.
In the third sample, $$$|1 - 4|\cdot|1 - 9|\cdot|4 - 9| = 3 \cdot 8 \cdot 5 = 120 \equiv 1 \bmod 7$$$.
