Virtual contest is a way to take part in past contest, as close as possible to participation on time. It is supported only ICPC mode for virtual contests.
If you've seen these problems, a virtual contest is not for you - solve these problems in the archive.
If you just want to solve some problem from a contest, a virtual contest is not for you - solve this problem in the archive.
Never use someone else's code, read the tutorials or communicate with other person during a virtual contest.

No tag edit access

The problem statement has recently been changed. View the changes.

×
F. Christmas Game

time limit per test

2 secondsmemory limit per test

256 megabytesinput

standard inputoutput

standard outputAlice and Bob are going to celebrate Christmas by playing a game with a tree of presents. The tree has $$$n$$$ nodes (numbered $$$1$$$ to $$$n$$$, with some node $$$r$$$ as its root). There are $$$a_i$$$ presents are hanging from the $$$i$$$-th node.

Before beginning the game, a special integer $$$k$$$ is chosen. The game proceeds as follows:

- Alice begins the game, with moves alternating each turn;
- in any move, the current player may choose some node (for example, $$$i$$$) which has depth at least $$$k$$$. Then, the player picks some positive number of presents hanging from that node, let's call it $$$m$$$ $$$(1 \le m \le a_i)$$$;
- the player then places these $$$m$$$ presents on the $$$k$$$-th ancestor (let's call it $$$j$$$) of the $$$i$$$-th node (the $$$k$$$-th ancestor of vertex $$$i$$$ is a vertex $$$j$$$ such that $$$i$$$ is a descendant of $$$j$$$, and the difference between the depth of $$$j$$$ and the depth of $$$i$$$ is exactly $$$k$$$). Now, the number of presents of the $$$i$$$-th node $$$(a_i)$$$ is decreased by $$$m$$$, and, correspondingly, $$$a_j$$$ is increased by $$$m$$$;
- Alice and Bob both play optimally. The player unable to make a move loses the game.

For each possible root of the tree, find who among Alice or Bob wins the game.

Note: The depth of a node $$$i$$$ in a tree with root $$$r$$$ is defined as the number of edges on the simple path from node $$$r$$$ to node $$$i$$$. The depth of root $$$r$$$ itself is zero.

Input

The first line contains two space-separated integers $$$n$$$ and $$$k$$$ $$$(3 \le n \le 10^5, 1 \le k \le 20)$$$.

The next $$$n-1$$$ lines each contain two integers $$$x$$$ and $$$y$$$ $$$(1 \le x, y \le n, x \neq y)$$$, denoting an undirected edge between the two nodes $$$x$$$ and $$$y$$$. These edges form a tree of $$$n$$$ nodes.

The next line contains $$$n$$$ space-separated integers denoting the array $$$a$$$ $$$(0 \le a_i \le 10^9)$$$.

Output

Output $$$n$$$ integers, where the $$$i$$$-th integer is $$$1$$$ if Alice wins the game when the tree is rooted at node $$$i$$$, or $$$0$$$ otherwise.

Example

Input

5 1 1 2 1 3 5 2 4 3 0 3 2 4 4

Output

1 0 0 1 1

Note

Let us calculate the answer for sample input with root node as 1 and as 2.

Root node 1

Alice always wins in this case. One possible gameplay between Alice and Bob is:

- Alice moves one present from node 4 to node 3.
- Bob moves four presents from node 5 to node 2.
- Alice moves four presents from node 2 to node 1.
- Bob moves three presents from node 2 to node 1.
- Alice moves three presents from node 3 to node 1.
- Bob moves three presents from node 4 to node 3.
- Alice moves three presents from node 3 to node 1.

Bob is now unable to make a move and hence loses.

Root node 2

Bob always wins in this case. One such gameplay is:

- Alice moves four presents from node 4 to node 3.
- Bob moves four presents from node 5 to node 2.
- Alice moves six presents from node 3 to node 1.
- Bob moves six presents from node 1 to node 2.

Alice is now unable to make a move and hence loses.

Codeforces (c) Copyright 2010-2021 Mike Mirzayanov

The only programming contests Web 2.0 platform

Server time: Jul/28/2021 13:54:48 (h3).

Desktop version, switch to mobile version.

Supported by

User lists

Name |
---|