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A. Potion-making

time limit per test

1 secondmemory limit per test

256 megabytesinput

standard inputoutput

standard outputYou have an initially empty cauldron, and you want to brew a potion in it. The potion consists of two ingredients: magic essence and water. The potion you want to brew should contain exactly $$$k\ \%$$$ magic essence and $$$(100 - k)\ \%$$$ water.

In one step, you can pour either one liter of magic essence or one liter of water into the cauldron. What is the minimum number of steps to brew a potion? You don't care about the total volume of the potion, only about the ratio between magic essence and water in it.

A small reminder: if you pour $$$e$$$ liters of essence and $$$w$$$ liters of water ($$$e + w > 0$$$) into the cauldron, then it contains $$$\frac{e}{e + w} \cdot 100\ \%$$$ (without rounding) magic essence and $$$\frac{w}{e + w} \cdot 100\ \%$$$ water.

Input

The first line contains the single $$$t$$$ ($$$1 \le t \le 100$$$) — the number of test cases.

The first and only line of each test case contains a single integer $$$k$$$ ($$$1 \le k \le 100$$$) — the percentage of essence in a good potion.

Output

For each test case, print the minimum number of steps to brew a good potion. It can be proved that it's always possible to achieve it in a finite number of steps.

Example

Input

3 3 100 25

Output

100 1 4

Note

In the first test case, you should pour $$$3$$$ liters of magic essence and $$$97$$$ liters of water into the cauldron to get a potion with $$$3\ \%$$$ of magic essence.

In the second test case, you can pour only $$$1$$$ liter of essence to get a potion with $$$100\ \%$$$ of magic essence.

In the third test case, you can pour $$$1$$$ liter of magic essence and $$$3$$$ liters of water.

Codeforces (c) Copyright 2010-2021 Mike Mirzayanov

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