A. Potion-making
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

You have an initially empty cauldron, and you want to brew a potion in it. The potion consists of two ingredients: magic essence and water. The potion you want to brew should contain exactly $k\ \%$ magic essence and $(100 - k)\ \%$ water.

In one step, you can pour either one liter of magic essence or one liter of water into the cauldron. What is the minimum number of steps to brew a potion? You don't care about the total volume of the potion, only about the ratio between magic essence and water in it.

A small reminder: if you pour $e$ liters of essence and $w$ liters of water ($e + w > 0$) into the cauldron, then it contains $\frac{e}{e + w} \cdot 100\ \%$ (without rounding) magic essence and $\frac{w}{e + w} \cdot 100\ \%$ water.

Input

The first line contains the single $t$ ($1 \le t \le 100$) — the number of test cases.

The first and only line of each test case contains a single integer $k$ ($1 \le k \le 100$) — the percentage of essence in a good potion.

Output

For each test case, print the minimum number of steps to brew a good potion. It can be proved that it's always possible to achieve it in a finite number of steps.

Example
Input
3
3
100
25

Output
100
1
4

Note

In the first test case, you should pour $3$ liters of magic essence and $97$ liters of water into the cauldron to get a potion with $3\ \%$ of magic essence.

In the second test case, you can pour only $1$ liter of essence to get a potion with $100\ \%$ of magic essence.

In the third test case, you can pour $1$ liter of magic essence and $3$ liters of water.