Codeforces Round 868 (Div. 2) |
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constructive algorithms

math

strings

*1900

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D. Unique Palindromes

time limit per test

2 secondsmemory limit per test

256 megabytesinput

standard inputoutput

standard outputA palindrome is a string that reads the same backwards as forwards. For example, the string abcba is palindrome, while the string abca is not.

Let $$$p(t)$$$ be the number of unique palindromic substrings of string $$$t$$$, i. e. the number of substrings $$$t[l \dots r]$$$ that are palindromes themselves. Even if some substring occurs in $$$t$$$ several times, it's counted exactly once. (The whole string $$$t$$$ is also counted as a substring of $$$t$$$).

For example, string $$$t$$$ $$$=$$$ abcbbcabcb has $$$p(t) = 6$$$ unique palindromic substrings: a, b, c, bb, bcb and cbbc.

Now, let's define $$$p(s, m) = p(t)$$$ where $$$t = s[1 \dots m]$$$. In other words, $$$p(s, m)$$$ is the number of palindromic substrings in the prefix of $$$s$$$ of length $$$m$$$. For example, $$$p($$$abcbbcabcb$$$, 5)$$$ $$$=$$$ $$$p($$$abcbb$$$) = 5$$$.

You are given an integer $$$n$$$ and $$$k$$$ "conditions" ($$$k \le 20$$$). Let's say that string $$$s$$$, consisting of $$$n$$$ lowercase Latin letters, is good if all $$$k$$$ conditions are satisfied at the same time. A condition is a pair $$$(x_i, c_i)$$$ and have the following meaning:

- $$$p(s, x_i) = c_i$$$, i. e. a prefix of $$$s$$$ of length $$$x_i$$$ contains exactly $$$c_i$$$ unique palindromic substrings.

Look in Notes if you need further clarifications.

Input

Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 10^4$$$). The description of the test cases follows.

The first line of each test case contains two integers $$$n$$$ and $$$k$$$ ($$$3 \le n \le 2 \cdot 10^5$$$; $$$1 \le k \le 20$$$) — length of good string $$$s$$$ and number of conditions.

The second line of each test case contains $$$k$$$ integers $$$x_1, x_2, \dots, x_k$$$ ($$$3 \le x_1 < x_2 < \dots < x_k = n$$$) where $$$x_i$$$ is the length of the prefix in the $$$i$$$-th condition.

The third line of each test case contains $$$k$$$ integers $$$c_1, c_2, \dots, c_k$$$ ($$$3 \le c_1 \le c_2 \le \dots \le c_k \le \min{\left(10^9, \frac{(n + 1) n}{2} \right)}$$$) where $$$c_i$$$ is the number of palindromic substrings in the $$$i$$$-th condition.

It is guaranteed that the sum of $$$n$$$ over all test cases does not exceed $$$2 \cdot 10 ^ 5$$$.

Output

For each test case, if there is no good string $$$s$$$ of length $$$n$$$ that satisfies all conditions, print NO.

Otherwise, print YES and a string $$$s$$$ of length $$$n$$$, consisting of lowercase Latin letters, that satisfies all conditions. If there are multiple answers, print any of them.

Example

Input

710 25 105 63 1334 23 43 34 23 43 44 14510 34 6 104 5 810 44 6 7 104 5 7 8

Output

YES abcbbcabcb YES foo YES ayda YES wada NO YES abcbcacbab NO

Note

In the first test case, string $$$s$$$ $$$=$$$ abcbbcabcb satisfies $$$k = 2$$$ conditions:

- $$$p(s, x_1) = p(s, 5) =$$$ $$$p($$$abcbb$$$) = 5 = s_1$$$. Palindromic substrings are a, b, c, bb and bcb.
- $$$p(s, x_2) = p(s, 10) =$$$ $$$p($$$abcbbcabcb$$$) = 6 = s_2$$$. Palindromic substrings are the same as above, and one extra substring cbbc.

In the second test case, string foo satisfies $$$k = 1$$$ condition:

- $$$p($$$foo$$$) = 3$$$. Palindromic substrings are f, o and oo.

In the third test case, string ayda satisfies $$$k = 2$$$ conditions:

- $$$p($$$ayd$$$) = 3$$$. Palindromic substrings are a, y and d.
- $$$p($$$ayda$$$) = 3$$$. Palindromic substrings are the same.

In the fourth test case, string wada satisfies $$$k = 2$$$ conditions:

- $$$p($$$wad$$$) = 3$$$. Palindromic substrings are w, a and d.
- $$$p($$$wada$$$) = 4$$$. Palindromic substrings are the same, and one extra substring ada.

In the fifth test case, it can be proven that there is no string of length $$$4$$$ which has $$$5$$$ palindromic substrings.

In the sixth test case, string abcbcacbab satisfies $$$k = 3$$$ conditions:

- $$$p($$$abcb$$$) = 4$$$. Palindromic substrings are a, b, c and bcb.
- $$$p($$$abcbca$$$) = 5$$$. Palindromic substrings are the same, and one extra substring cbc.
- $$$p($$$abcbcacbab$$$) = 8$$$. Palindromic substrings are the same, and three extra substrings cac, bab and bcacb.

Codeforces (c) Copyright 2010-2023 Mike Mirzayanov

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