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Alternative solution for a problem
Good day everybody,
I've been going true some old problems and I've found this problem: 453B - Little Pony and Harmony Chest
And I've been wondering why can't I just cout [sum of (A0,A1,A2,...,AN) — N] and cout 1, N times ?
I'd be harmony sequence and it'd minimaze the sum.
I tryed subminting solution that did that but it failed.
Can someone explain why is this wrong?
