~~~~~↵
vector<int> v;↵
cout<<v.size()-1;↵
~~~~~↵
↵
The following will give you `18446744073709551615`. This is because `vector.size()` returns a `size_t` type value, which is an alias for `unsigned long int`. In plain terms:↵
↵
~~~~~↵
unsigned long int a=0;↵
cout<<a-1;↵
~~~~~↵
↵
The above code will give the same result — `18446744073709551615`. ↵
↵
### Implications↵
↵
↵
~~~~~↵
for(int i=0;i<vector.size()-1;i++){↵
...↵
}↵
~~~~~↵
↵
In the above for loop, if the vector has 0 elements, then the loop will be equivalent to:↵
↵
↵
~~~~~↵
for(int i=0;i<18446744073709551615;i++){↵
...↵
}↵
~~~~~↵
↵
Which, I believe is not what you will be expecting. So the correct way to use for loops is the following:↵
↵
↵
~~~~~↵
for(int i=0;(i+1)<vector.size();i++){↵
...↵
}↵
~~~~~
vector<int> v;↵
cout<<v.size()-1;↵
~~~~~↵
↵
The following will give you `18446744073709551615`. This is because `vector.size()` returns a `size_t` type value, which is an alias for `unsigned long int`. In plain terms:↵
↵
~~~~~↵
unsigned long int a=0;↵
cout<<a-1;↵
~~~~~↵
↵
The above code will give the same result — `18446744073709551615`. ↵
↵
### Implications↵
↵
↵
~~~~~↵
for(int i=0;i<vector.size()-1;i++){↵
...↵
}↵
~~~~~↵
↵
In the above for loop, if the vector has 0 elements, then the loop will be equivalent to:↵
↵
↵
~~~~~↵
for(int i=0;i<18446744073709551615;i++){↵
...↵
}↵
~~~~~↵
↵
Which, I believe is not what you will be expecting. So the correct way to use for loops is the following:↵
↵
↵
~~~~~↵
for(int i=0;(i+1)<vector.size();i++){↵
...↵
}↵
~~~~~
