a = 0
while max(V) > 0:
C = [ 0 ] * max(V)
for x in V:
if x%2==0:
a += C[x//2]
else:
C[x//2] += 1
V = [ x//2 for x in V ]
print(a)
№ | Пользователь | Рейтинг |
---|---|---|
1 | jiangly | 3640 |
2 | Benq | 3593 |
3 | tourist | 3572 |
4 | orzdevinwang | 3561 |
5 | cnnfls_csy | 3539 |
6 | ecnerwala | 3534 |
7 | Radewoosh | 3532 |
8 | gyh20 | 3447 |
9 | Rebelz | 3409 |
10 | Geothermal | 3408 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | maomao90 | 173 |
2 | adamant | 164 |
3 | awoo | 161 |
4 | TheScrasse | 160 |
5 | nor | 159 |
6 | maroonrk | 156 |
7 | SecondThread | 152 |
8 | pajenegod | 146 |
9 | BledDest | 144 |
10 | Um_nik | 143 |
How does Counting Inversions work in the following code?
a = 0
while max(V) > 0:
C = [ 0 ] * max(V)
for x in V:
if x%2==0:
a += C[x//2]
else:
C[x//2] += 1
V = [ x//2 for x in V ]
print(a)
Название |
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