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Minimum time to reach destination with matrix cells getting banned

Правка en4, от swordx, 2021-06-13 09:25:41

Problem: Given a matrix of dimension m*n. There are x number of penguins standing on some cell(i,j) in the matrix initially(none of the penguin are on the same cell). And there are some safe spots/cells in the matrix. Our job is figure out the minimum time for penguins to reach the safe spot with following conditions:

1. If a spot is already taken by some penguin, any other penguin cannot take that spot.
2. While traversing, If some penguin passes through cell (i,j) in its path to reach some safe spot, it is banned for other penguins to use that cell.

Print -1 in case if it not possible for all penguins to reach to some safe spot.

Penguins can move in four directions i.e either up, down, left, right. All penguins can move to one of the adjacent cells in 1 unit of time.

Let me know if the problem statement is not clear.

Test case:

P1 . . P2

. S S .

. . . .

S S . .

P1 and P2 are penguins and they are standing on cell (0,0) and (0,3) initially and there are multiple safe spot in this example located at (1,1), (1,2), (3,0) and (3,1). The minimum time for both penguin to reach at the safe spot will be 2.

Output: 2

Test case:

. S . .

P1 . P2 P3

. S S .

. . . .

Output: 2

There is a single solution possible for this test case, P1 has to follow:(1,0)->(0,0)->(0,1), P1 cannot use the path:(1,0)->(1,1)->(0,1) because if P1 uses this path then (1,1) will get banned for P2 to use and we won't be able to take P2 on safe spot.

#### История

Правки

Rev. Язык Кто Когда Δ Комментарий
en4 swordx 2021-06-13 09:25:41 16
en3 swordx 2021-06-13 09:03:18 690
en2 swordx 2021-06-12 22:21:39 54
en1 swordx 2021-06-12 15:22:47 861 Initial revision (published)