By awoo, history, 2 weeks ago, translation, In English

Hello Codeforces!

On Nov/22/2021 12:35 (Moscow time) Educational Codeforces Round 117 (Rated for Div. 2) will start.

The problems are based on the Southern Russia and Volga Cup 2021, which is a regional contest of ICPC. If you have participated in it or are planning to play it as a virtual contest, please refrain from taking part in the Educational Round.

Series of Educational Rounds continue being held as Harbour.Space University initiative! You can read the details about the cooperation between Harbour.Space University and Codeforces in the blog post.

This round will be rated for the participants with rating lower than 2100. It will be held on extended ICPC rules. The penalty for each incorrect submission until the submission with a full solution is 10 minutes. After the end of the contest you will have 12 hours to hack any solution you want. You will have access to copy any solution and test it locally.

You will be given 6 or 7 problems and 2 hours to solve them.

The problems were invented and prepared by Adilbek adedalic Dalabaev, Vladimir vovuh Petrov, Ivan BledDest Androsov, Maksim Neon Mescheryakov, Roman Roms Glazov and me. Also huge thanks to Mike MikeMirzayanov Mirzayanov for great systems Polygon and Codeforces.

Good luck to all the participants!

UPD: Editorial is out.

 
 
 
 
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2 weeks ago, # |
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NOTE THE UNUSUAL TIMING

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eagerly waiting for the contest.

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Why Unusual timing again? :(

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Finally After 7 days. Thank You.

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2 weeks ago, # |
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Finally a cf contest after so long .....All the best to the fellow programmers !!

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2 weeks ago, # |
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I look at the unusual timing of the contest. I take a mental note so that I do not miss the contest. I miss the contest anyway.

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2 weeks ago, # |
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contest after long time in unusual time , why in the last period the contests in unusual time :(

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On behalf of all Russian schoolers, I protest against the unusual timings on weekdays.

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On behalf of myself I strongly support the unusual timing, it gives an opportunity for competitors around the world to participate :)

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Will try to perform better this time. let's hope for the best. Good luck everyone!

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Good luck everyone!

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and for you!

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I hope you will done the best

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Last week one contest this week five contest I am not complaining, but it would have been better if contests evenly spaced them in these two weeks. Lately, there has been a lot of inconsistency in contests either there are very few, or there is a lot in a 7 to 10 days period. Anyway, today is contest day, so best of luck to everyone.

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Good luck for you! Good luck for me! Good luck for everybody ~

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2 weeks ago, # |
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Can you change the timing i have meeting from 4:00 to 4:30 pm , please

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Will the problems be arranged in the correct difficulty order? Or will it be shuffled as we see in icpc?

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But Is It Rated?

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2 weeks ago, # |
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Mathforces

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How to solve D?

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How to solve E?

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    2 weeks ago, # ^ |
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    i did it using ternary search on the number of messages to be pinned , and then selected the books in a greedy way, got tle on tc 149 , but after one optimization it ran comfortably. Update: the solution was wrong

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      2 weeks ago, # ^ |
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      thx, got it

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      2 weeks ago, # ^ |
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      Your function isn't parabola or convex. When T(len of answer) is [1; 20], ur function gets chaotic values. When T is [21; 2e5] fucntion decreases on all segment

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      2 weeks ago, # ^ |
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      Your ternary search solution has been hacked :)

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best contest i've ever done!

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Does anyone know the proof for why it's never optimal to select more than 20 pins in 1612E - Messages??

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    2 weeks ago, # ^ |
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    If $$$s_i$$$ is the sum of all $$$k_i$$$ with $$$m_i = i$$$, then the expected return you get from including $$$i$$$ is equal to $$$\frac{s_i}{t}$$$ if $$$t \geq 20$$$. Note that you greedily want to select the largest $$$t$$$ values of this for the messages, and you can show that this value is greatest when $$$t = 20$$$ (since averages decrease since you're taking lower and lower sums).

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      2 weeks ago, # ^ |
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      I mean many people made the guess for first 20 but I wasn't smart enough ig.

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    2 weeks ago, # ^ |
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    If you take 20 best messages out of $$$m$$$ taken in terms of expected value contribution and leave just them, their expected value will increase proportionally to $$$\frac{m}{20}$$$. But since they were maximal total EV will not decrease.

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    2 weeks ago, # ^ |
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    Suppose we have selected the $$$y$$$ messages with the max $$$x$$$, where $$$y$$$ $$$\geq$$$ $$$20$$$, and $$$\sum{k_i}$$$ $$$=$$$ $$$x$$$ for all $$$i$$$ where $$$i$$$ is one of the chosen messages. If we select the $$$(y+1)_{th}$$$ message $$$msg$$$ where $$$\sum{k_j}$$$ $$$=$$$ $$$z$$$ for all $$$j$$$ where $$$m_j$$$ = $$$msg$$$, the first $$$y$$$ messages are still the best, and their total expected value decreased from $$$\frac{x}{y}$$$ to $$$\frac{x}{y+1}$$$, that is, decreased by $$$\frac{x/y}{y+1}$$$. However, $$$msg$$$ only introduced $$$\frac{z}{y+1}$$$, and $$$z$$$ $$$\leq$$$ $$$\frac{x}{y}$$$, otherwise it would be one of the best $$$y$$$ messages.

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idk how many guys pass G, I want to say that F is much easier than G

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    2 weeks ago, # ^ |
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    When I began solving G, it had 17 solves while F had like 3.

    Most people who reached F/G didn't have time to solve both, so it was probably just an observer effect here.

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    2 weeks ago, # ^ |
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    Hi, can you please give some hints on how to solve F? For me G seemed easier than F.

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      2 weeks ago, # ^ |
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      You can just optimize bfs.

      The queue contains tuples $$$(a, b, d)$$$ ($$$d$$$ is the number of moves to reach $$$(a, b)$$$). Let $$$(a, b, d)$$$ be a useless tuple if there exists a tuple $$$(a', b', d)$$$ in the queue, with $$$a' > a$$$ and $$$b' > b$$$. If you remove useless tuples from the queue (e.g. by rebuilding the whole queue if its size is $$$> 2 \cdot 10^5$$$), the bfs is fast enough.

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How to solve D ? I called gcd(difference, maximum number % difference), but if the difference is larger, then it gets executed huge number of times...

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    2 weeks ago, # ^ |
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    Basically, the numbers you can reach are everything reached by the Euclidean algorithm for a and b.

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      [user:Agnimandur]can u plz see my C solution I tried it in O(1) can u plz try this approach and tells whats wrong i spend about an hour but didn't got anything thnx in advance

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    2 weeks ago, # ^ |
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    I guess resultant number was eventually max-min*k such that max-min*k>=min after that max and min will change so you just have to check whether x%min==max%min otherwise pass for min,max%min

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Hmm... I think G is easier than E. E was difficult to translate.

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I dont know how total accepted submissions of problem D went from around 1200 to 1700 in last 20 minutes ;_;

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traditional -100 for me kekw

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EDIT: ok i got the mistake.

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i should've been prepared more before joining this round

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Can Anyone provide the intuition behind D, it ate up my whole hour, still couldn't find a logic.

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    2 weeks ago, # ^ |
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    When assignment operations are only based on substraction of two no.s . Think GCD .

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      i tried GCDs, but idk how to actually solve

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        2 weeks ago, # ^ |
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        Go through the same procedure as GCD , and before recurring for GCD(b%a,a) check that whether (b%a)+(j*a) is equal to x or not , j is from 0->r such that (b%a)+((r+1)*a) is greater than b . For clearity refer this https://codeforces.com/contest/1612/submission/136448350

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          2 weeks ago, # ^ |
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          Great, Many thanks to you

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          13 days ago, # ^ |
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          Can you please explain this part? I would be very thankful to you.

          Code
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            13 days ago, # ^ |
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            As I said before if x's value is b%a+(j*a) where j is 0 to r , then x is achievable . So x=(b%a)+(j*a) => x-(b%a)=j*a => (x-(b%a))%a=0 , as j*a%a=0

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Should E really pass in $$$O(nlogn*20)$$$? I did write a solution which passes but with a high execution time. Can someone hack it?

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Did anyone observed precision handling error in python in question 3

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    2 weeks ago, # ^ |
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    Yeah, got a WA on test 3...

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    Yes — do use from decimal import Decimal to handle floating point numbers with higher precision in Python.

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What's the approach for E?

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    2 weeks ago, # ^ |
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    Observation 1: if you're going to pick X messages, it's obviously optimal to choose the mi such that sum(min(ki,X)) is maximised (why? consider how you would write the expectation calculation as an equation). So the first thing we want to do is sort the messages by the sum of ki values assigned to that value of mi.

    Observation 2: it's never optimal to go beyond 20 messages (or, more specifically, max(ki) messages). Why? Suppose we have exactly max(ki) messages. Then our expected value is E20 = sum(ki)/20 for the users whose messages are in this set of 20. If we add another message, the expected value E21 = sum(ki_prev)/21 + sum(ki_21)/21 = E20*(20/21) + sum(ki_21)/21. Suppose E21 > E20. Then we have sum(ki_21)/21 > E20*(1/21) = sum(ki_prev)/(20*21), and hence sum(ki_21) > sum(ki_prev)/20. This means that the 21st message has a greater sum of ki values than the mean of the first 20. But this is impossible because the 21st message has a sum of ki values less than or equal to the first 20 values.

    So it's proven we will never go beyond 20 messages. Now we just try all possible values from 1 to 20, and find which gives the greatest expectation. There's a tricky nuance (which I believe I got wrong in contest) where you have to sort each time according to sum(min(ki,X)), rather than just sorting according to sum(ki).

    Code

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      2 weeks ago, # ^ |
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      And you don't even have to make the second observation, I, for one, completely missed it. You can just sort all E20 highest to lowest and check all prefixes of this order.

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      2 weeks ago, # ^ |
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      I Was looking for this proof precisely, Thank You for the clear explanation !

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who wants to be my friend? round was goooooood_)

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How to solve C?

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    2 weeks ago, # ^ |
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    You can use binary search method in which search space is 1 to 2*k-1. For any i>=1 if its possible to send message then any j where 1>=j<i is also possible.

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    13 days ago, # ^ |
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    for me i change that problem to math and solve the quadratic equation

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Regarding this submission: https://codeforces.com/contest/1612/submission/136484148

If I'm not wrong, it's complexity is clearly $$$O(t * 10^6)$$$ for cases which results in -1 -1. So, it must exceed the given time limit easily (as $$$t \leq 3000$$$), but on Custom Invocation I have tried and it runs in $$$\sim 1500$$$ ms.

Can anyone kindly explain me why it is so?

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How to solve F?

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Can someone explain their approach to Problem D

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What's the hack case on E?

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Here are the video Solutions to the first 5 Problems In case you are interested.

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Thanks for the good sample tests to avoid overflow in problem C.

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Here's a heuristic solution for problem F: https://codeforces.com/contest/1612/submission/136557294

The idea is that it's generally much better to replace the smaller number to increase our power quickly (which greatly overpowers any gain from synergies), but for small values this might not be the best option. We take all possible choices for the first 6 moves, and then apply the following:

  • If $$$x$$$ or $$$y$$$ is already maximized, then replace the other.
  • If one of $$$x$$$ or $$$y$$$ can be maximized on the next move, then do that.
  • Otherwise, do whatever will increase power the most.

This passes all test cases but I highly doubt it is correct, and would welcome a valid hack.

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To not keep you waiting, the ratings are updated preliminarily. In a few hours/days, I will remove cheaters and update the ratings again!

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I panicked in this contest and lost a bunch of ratings. My biggest drop yet (-100). I couldn't even solve A. Is there anything I can do to get a better grip of my nerves in a contest and not panic when I see an implementation heavy or math problem in the contest?

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13 days ago, # |
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164 pretests in E and still they do not have tc that fails the most obvious wrong solution)

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What kind of time of sending tutorial is normal? Looking forward to the solution.QWQ

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who made this fucking problem write in the comments!

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My solution coincides with another user know what can i do ?

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Auto comment: topic has been updated by awoo (previous revision, new revision, compare).

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I received a System mail saying that my solution 136459207 matches with idkmyname_ submission 136471505. I believe this is because we both have used nor's publically available BigInt library
I had also put this link as a comment in my code, as one should do while copying third-party code. MikeMirzayanov please look into this

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I got this email from Codeforces which says that my solution for problem C coincides with too many people.

It goes like- Attention!

Your solution 136470651 for the problem 1612C significantly coincides with solutions bihari_bandar/136430343, greyman/136431111, going-too-far/136431248, SnigdhaReddy27/136438434, Jee_none/136440961, loser53/136448455, Pratyush_tripathi/136449209, manishchembeti/136452512, yash112124/136453654, misra99/136456090, ashutoshtr/136458047, TheThinker_08/136458129, venom0912/136460586, Secret_Superstar12/136461961, pratik2912/136462123, shivam.yadav98939294/136462732, Karan10100/136462833, 123Alpha/136465897, crosscheck371/136466967, darkcoder_347/136470103, codeprakhar/136470651, ramanand_rv/136470925, noob_tusharb/136471502. Such a coincidence is a clear rules violation. Note that unintentional leakage is also a violation. For example, do not use ideone.com with the default settings (public access to your code). If you have conclusive evidence that a coincidence has occurred due to the use of a common source published before the competition, write a comment to post about the round with all the details. More information can be found at http://codeforces.com/blog/entry/8790. Such violation of the rules may be the reason for blocking your account or other penalties. In case of repeated violations, your account may be blocked.

Now, I don't understand how my solution can so perfectly coincide with so many people even when I don't know who they are! I even have never used Ideone.com.

I was previously trying to solve this question using simple maths(quadratic equation solution) but that didn't work so I thought of another method that involved simple binary search. It worked.

I understand that the code of binary search is freely available at almost any programming website which leads to this coincidence.

Codeforces community... How can I get this fixed?

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    13 days ago, # ^ |
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    Please look into this matter MikeMirzayanov

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    why does this kind of coincidences always happens to indians?

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      At least compare my solution with others before demeaning India or its coders.

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        13 days ago, # ^ |
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        yes

        you just changed the names of the variables

        just another dirty indian still lying after being caught

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          13 days ago, # ^ |
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          Yes Sir It was my bad to argue with you. You are absolutely correct! :)

          Though your mind is still filthy like your DP.

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            13 days ago, # ^ |
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            ohno i smell dead bodies!!

            did you took a bath in the Genzies river today?

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              13 days ago, # ^ |
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              Haha Nothing like that exists

              Don't even know the names of rivers. Poor boy

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                13 days ago, # ^ |
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                its the river that all indians uses as a toilet and throughes away dead bodies and drinks from it

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I have received a mail from the system stating that my code for 1st,2nd, 3rd and 4th question coincide. First question, was easy it was simple geometry question, so same thinking can be possible. In the second question, I have used visited array(bfs type approach) which can come in many peoples mind and as it's an algorithm so coincidence in code can happen. For 3rd question I have used binary search template which I get from leetcode I have to write check(condition function) function so it may be possible many people are using that template. For the 4th question, I have used swapping and modulus to check whether the number is x-magic pair or not, which can come in many people's mind. I have not used any public Ide, I have used vs code in the contest. MikeMirzayanov, please consider it, I have not copy or share my code anywhere, It is merely coincidence.

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13 days ago, # |
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When will they roll out the rating for this contest?

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13 days ago, # |
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MikeMirzayanov I got an email from the system that one of my solutions for this round coincides with many others. Although I still can't understand why it happened;

The main concern is that All the problems for this contest were skipped from evaluation but still, my rating went down by -108. If the contest was skipped; shouldn't the rating neither increase nor decrease?

Please look into it and return my rating like before this contest. Thank You

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13 days ago, # |
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12 days ago, # |
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I want to ask question F, if I just think about q=0, does it have the same number of answers as it has the right answer? How long does it take for the Fibonacci number to form Max of m,n

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5 days ago, # |
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Hello everybody. Can anybody tell me what is the main point to solve problem E? Thank you for your answers. Link to the problem. And also thank you for the contest. awoo