F. DFS
time limit per test
6 seconds
memory limit per test
512 megabytes
input
standard input
output
standard output

Let $T$ be a tree on $n$ vertices. Consider a graph $G_0$, initially equal to $T$. You are given a sequence of $q$ updates, where the $i$-th update is given as a pair of two distinct integers $u_i$ and $v_i$.

For every $i$ from $1$ to $q$, we define the graph $G_i$ as follows:

• If $G_{i-1}$ contains an edge $\{u_i, v_i\}$, then remove this edge to form $G_i$.
• Otherwise, add this edge to $G_{i-1}$ to form $G_i$.

Formally, $G_i := G_{i-1} \triangle \{\{u_i, v_i\}\}$ where $\triangle$ denotes the set symmetric difference.

Furthermore, it is guaranteed that $T$ is always a subgraph of $G_i$. In other words, an update never removes an edge of $T$.

Consider a connected graph $H$ and run a depth-first search on it. One can see that the tree edges (i.e. the edges leading to a not yet visited vertex at the time of traversal) form a spanning tree of the graph $H$. This spanning tree is not generally fixed for a particular graph — it depends on the starting vertex, and on the order in which the neighbors of each vertex are traversed.

We call vertex $w$ good if one can order the neighbors of each vertex in such a way that the depth-first search started from $w$ produces $T$ as the spanning tree. For every $i$ from $1$ to $q$, find and report the number of good vertices.

Input

The first line contains two integers $n$ and $q$ ($3 \le n \le 2\cdot 10^5$, $1 \le q \le 2 \cdot 10^5$) — the number of nodes and the number of updates, respectively.

Each of the next $n-1$ lines contains two integers $u$ and $v$ ($1 \le u, v \le n$, $u \ne v$) — vertices connected by an edge in $T$. It is guaranteed that this graph is a tree.

Each of the next $q$ lines contains two integers $u$ and $v$ ($1 \le u, v \le n$, $u \ne v$) — the endpoints of the edge that is added or removed. It is guaranteed that this edge does not belong to $T$.

Output

For each update, print one integer $k$ — the number of good vertices $w$ after the corresponding update.

Examples
Input
3 21 21 32 33 2
Output
23
Input
6 61 22 31 44 51 62 53 45 26 43 46 5
Output
323232
Note

The first sample is depicted in the following figure. After the first update, $G$ contains all three possible edges. The result of a DFS is as follows:

• Let the starting vertex be $1$. We have two choices of ordering the neighbors of $1$, either $[2, 3]$ or $[3, 2]$.
• If we choose the former, then we reach vertex $2$. Regardless of the ordering of its neighbors, the next visited vertex will be $3$. Thus, the spanning tree generated by this DFS will contain edges $\{1, 2\}$ and $\{2, 3\}$, which does not equal to $T$.
• If we choose the latter, we obtain a spanning tree with edges $\{1, 3\}$ and $\{2, 3\}$.
Hence, there is no way of ordering the neighbors of vertices such that the DFS produces $T$, and subsequently $1$ is not a good vertex.
• Let the starting vertex be $2$. We have two choices of traversing its neighbors. If we visit $3$ first, then the spanning tree will consist of edges $\{2,3\}$ and $\{1,3\}$, which is not equal to $T$. If we, however, visit $1$ first, then we can only continue to $3$ from here, and the spanning tree will consist of edges $\{1, 2\}$ and $\{1,3\}$, which equals to $T$. Hence, $2$ is a good vertex.
• The case when we start in the vertex $3$ is symmetrical to starting in $2$, and hence $3$ is a good vertex.
Therefore, the answer is $2$.

After the second update, the edge between $2$ and $3$ is removed, and $G = T$. It follows that the spanning tree generated by DFS will be always equal to $T$ independent of the choice of the starting vertex. Thus, the answer is $3$.

In the second sample, the set of good vertices after the corresponding query is:

• $\{2, 3, 5\}$
• $\{3, 5\}$
• $\{3, 4, 5\}$
• $\{4, 5\}$
• $\{4, 5, 6\}$
• $\{5, 6\}$