Virtual contest is a way to take part in past contest, as close as possible to participation on time. It is supported only ICPC mode for virtual contests.
If you've seen these problems, a virtual contest is not for you - solve these problems in the archive.
If you just want to solve some problem from a contest, a virtual contest is not for you - solve this problem in the archive.
Never use someone else's code, read the tutorials or communicate with other person during a virtual contest.

No tag edit access

B. Yet Another Meme Problem

time limit per test

1 secondmemory limit per test

256 megabytesinput

standard inputoutput

standard outputTry guessing the statement from this picture http://tiny.cc/ogyoiz.

You are given two integers $$$A$$$ and $$$B$$$, calculate the number of pairs $$$(a, b)$$$ such that $$$1 \le a \le A$$$, $$$1 \le b \le B$$$, and the equation $$$a \cdot b + a + b = conc(a, b)$$$ is true; $$$conc(a, b)$$$ is the concatenation of $$$a$$$ and $$$b$$$ (for example, $$$conc(12, 23) = 1223$$$, $$$conc(100, 11) = 10011$$$). $$$a$$$ and $$$b$$$ should not contain leading zeroes.

Input

The first line contains $$$t$$$ ($$$1 \le t \le 100$$$) — the number of test cases.

Each test case contains two integers $$$A$$$ and $$$B$$$ $$$(1 \le A, B \le 10^9)$$$.

Output

Print one integer — the number of pairs $$$(a, b)$$$ such that $$$1 \le a \le A$$$, $$$1 \le b \le B$$$, and the equation $$$a \cdot b + a + b = conc(a, b)$$$ is true.

Example

Input

3 1 11 4 2 191 31415926

Output

1 0 1337

Note

There is only one suitable pair in the first test case: $$$a = 1$$$, $$$b = 9$$$ ($$$1 + 9 + 1 \cdot 9 = 19$$$).

Codeforces (c) Copyright 2010-2020 Mike Mirzayanov

The only programming contests Web 2.0 platform

Server time: Apr/07/2020 13:56:40 (f3).

Desktop version, switch to mobile version.

Supported by

User lists

Name |
---|