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brute force

dp

greedy

two pointers

*1500

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C. Good String

time limit per test

2 secondsmemory limit per test

256 megabytesinput

standard inputoutput

standard outputLet's call left cyclic shift of some string $$$t_1 t_2 t_3 \dots t_{n - 1} t_n$$$ as string $$$t_2 t_3 \dots t_{n - 1} t_n t_1$$$.

Analogically, let's call right cyclic shift of string $$$t$$$ as string $$$t_n t_1 t_2 t_3 \dots t_{n - 1}$$$.

Let's say string $$$t$$$ is good if its left cyclic shift is equal to its right cyclic shift.

You are given string $$$s$$$ which consists of digits 0–9.

What is the minimum number of characters you need to erase from $$$s$$$ to make it good?

Input

The first line contains single integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

Next $$$t$$$ lines contains test cases — one per line. The first and only line of each test case contains string $$$s$$$ ($$$2 \le |s| \le 2 \cdot 10^5$$$). Each character $$$s_i$$$ is digit 0–9.

It's guaranteed that the total length of strings doesn't exceed $$$2 \cdot 10^5$$$.

Output

For each test case, print the minimum number of characters you need to erase from $$$s$$$ to make it good.

Example

Input

3 95831 100120013 252525252525

Output

3 5 0

Note

In the first test case, you can erase any $$$3$$$ characters, for example, the $$$1$$$-st, the $$$3$$$-rd, and the $$$4$$$-th. You'll get string 51 and it is good.

In the second test case, we can erase all characters except 0: the remaining string is 0000 and it's good.

In the third test case, the given string $$$s$$$ is already good.

Codeforces (c) Copyright 2010-2023 Mike Mirzayanov

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