Codeforces Round 726 (Div. 2) |
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Finished |

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binary search

brute force

dp

greedy

hashing

implementation

string suffix structures

strings

two pointers

*1600

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E1. Erase and Extend (Easy Version)

time limit per test

2 secondsmemory limit per test

256 megabytesinput

standard inputoutput

standard outputThis is the easy version of the problem. The only difference is the constraints on $$$n$$$ and $$$k$$$. You can make hacks only if all versions of the problem are solved.

You have a string $$$s$$$, and you can do two types of operations on it:

- Delete the last character of the string.
- Duplicate the string: $$$s:=s+s$$$, where $$$+$$$ denotes concatenation.

You can use each operation any number of times (possibly none).

Your task is to find the lexicographically smallest string of length exactly $$$k$$$ that can be obtained by doing these operations on string $$$s$$$.

A string $$$a$$$ is lexicographically smaller than a string $$$b$$$ if and only if one of the following holds:

- $$$a$$$ is a prefix of $$$b$$$, but $$$a\ne b$$$;
- In the first position where $$$a$$$ and $$$b$$$ differ, the string $$$a$$$ has a letter that appears earlier in the alphabet than the corresponding letter in $$$b$$$.

Input

The first line contains two integers $$$n$$$, $$$k$$$ ($$$1 \leq n, k \leq 5000$$$) — the length of the original string $$$s$$$ and the length of the desired string.

The second line contains the string $$$s$$$, consisting of $$$n$$$ lowercase English letters.

Output

Print the lexicographically smallest string of length $$$k$$$ that can be obtained by doing the operations on string $$$s$$$.

Examples

Input

8 16 dbcadabc

Output

dbcadabcdbcadabc

Input

4 5 abcd

Output

aaaaa

Note

In the first test, it is optimal to make one duplication: "dbcadabc" $$$\to$$$ "dbcadabcdbcadabc".

In the second test it is optimal to delete the last $$$3$$$ characters, then duplicate the string $$$3$$$ times, then delete the last $$$3$$$ characters to make the string have length $$$k$$$.

"abcd" $$$\to$$$ "abc" $$$\to$$$ "ab" $$$\to$$$ "a" $$$\to$$$ "aa" $$$\to$$$ "aaaa" $$$\to$$$ "aaaaaaaa" $$$\to$$$ "aaaaaaa" $$$\to$$$ "aaaaaa" $$$\to$$$ "aaaaa".

Codeforces (c) Copyright 2010-2024 Mike Mirzayanov

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