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B. MIN-MEX Cut

time limit per test

1 secondmemory limit per test

256 megabytesinput

standard inputoutput

standard outputA binary string is a string that consists of characters $$$0$$$ and $$$1$$$.

Let $$$\operatorname{MEX}$$$ of a binary string be the smallest digit among $$$0$$$, $$$1$$$, or $$$2$$$ that does not occur in the string. For example, $$$\operatorname{MEX}$$$ of $$$001011$$$ is $$$2$$$, because $$$0$$$ and $$$1$$$ occur in the string at least once, $$$\operatorname{MEX}$$$ of $$$1111$$$ is $$$0$$$, because $$$0$$$ and $$$2$$$ do not occur in the string and $$$0 < 2$$$.

A binary string $$$s$$$ is given. You should cut it into any number of substrings such that each character is in exactly one substring. It is possible to cut the string into a single substring — the whole string.

A string $$$a$$$ is a substring of a string $$$b$$$ if $$$a$$$ can be obtained from $$$b$$$ by deletion of several (possibly, zero or all) characters from the beginning and several (possibly, zero or all) characters from the end.

What is the minimal sum of $$$\operatorname{MEX}$$$ of all substrings pieces can be?

Input

The input consists of multiple test cases. The first line contains a single integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases. Description of the test cases follows.

Each test case contains a single binary string $$$s$$$ ($$$1 \le |s| \le 10^5$$$).

It's guaranteed that the sum of lengths of $$$s$$$ over all test cases does not exceed $$$10^5$$$.

Output

For each test case print a single integer — the minimal sum of $$$\operatorname{MEX}$$$ of all substrings that it is possible to get by cutting $$$s$$$ optimally.

Example

Input

6 01 1111 01100 101 0000 01010

Output

1 0 2 1 1 2

Note

In the first test case the minimal sum is $$$\operatorname{MEX}(0) + \operatorname{MEX}(1) = 1 + 0 = 1$$$.

In the second test case the minimal sum is $$$\operatorname{MEX}(1111) = 0$$$.

In the third test case the minimal sum is $$$\operatorname{MEX}(01100) = 2$$$.

Codeforces (c) Copyright 2010-2022 Mike Mirzayanov

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