Codeforces Round 864 (Div. 2) |
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Finished |

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data structures

dfs and similar

divide and conquer

dsu

trees

*3000

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F. Li Hua and Path

time limit per test

2 secondsmemory limit per test

256 megabytesinput

standard inputoutput

standard outputLi Hua has a tree of $$$n$$$ vertices and $$$n-1$$$ edges. The vertices are numbered from $$$1$$$ to $$$n$$$.

A pair of vertices $$$(u,v)$$$ ($$$u < v$$$) is considered cute if exactly one of the following two statements is true:

- $$$u$$$ is the vertex with the minimum index among all vertices on the path $$$(u,v)$$$.
- $$$v$$$ is the vertex with the maximum index among all vertices on the path $$$(u,v)$$$.

There will be $$$m$$$ operations. In each operation, he decides an integer $$$k_j$$$, then inserts a vertex numbered $$$n+j$$$ to the tree, connecting with the vertex numbered $$$k_j$$$.

He wants to calculate the number of cute pairs before operations and after each operation.

Suppose you were Li Hua, please solve this problem.

Input

The first line contains the single integer $$$n$$$ ($$$2\le n\le 2\cdot 10^5$$$) — the number of vertices in the tree.

Next $$$n-1$$$ lines contain the edges of the tree. The $$$i$$$-th line contains two integers $$$u_i$$$ and $$$v_i$$$ ($$$1\le u_i,v_i\le n$$$; $$$u_i\ne v_i$$$) — the corresponding edge. The given edges form a tree.

The next line contains the single integer $$$m$$$ ($$$1\le m\le 2\cdot 10^5$$$) — the number of operations.

Next $$$m$$$ lines contain operations — one operation per line. The $$$j$$$-th operation contains one integer $$$k_j$$$ ($$$1\le k_j < n+j$$$) — a vertex.

Output

Print $$$m+1$$$ integers — the number of cute pairs before operations and after each operation.

Example

Input

7 2 1 1 3 1 4 4 6 4 7 6 5 2 5 6

Output

11 15 19

Note

The initial tree is shown in the following picture:

There are $$$11$$$ cute pairs — $$$(1,5),(2,3),(2,4),(2,6),(2,7),(3,4),(3,6),(3,7),(4,5),(5,7),(6,7)$$$.

Similarly, we can count the cute pairs after each operation and the result is $$$15$$$ and $$$19$$$.

Codeforces (c) Copyright 2010-2024 Mike Mirzayanov

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