D. Game of Stacks
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

You have $n$ stacks $r_1,r_2,\ldots,r_n$. Each stack contains some positive integers ranging from $1$ to $n$.

Define the following functions:

function init(pos):    stacks := an array that contains n stacks r[1], r[2], ..., r[n]    return get(stacks, pos)function get(stacks, pos):    if stacks[pos] is empty:        return pos    else:        new_pos := the top element of stacks[pos]        pop the top element of stacks[pos]        return get(stacks, new_pos)

You want to know the values returned by $\texttt{init(1)}, \texttt{init(2)}, \ldots, \texttt{init(n)}$.

Note that, during these calls, the stacks $r_1,r_2,\ldots,r_n$ don't change, so the calls $\texttt{init(1)}, \texttt{init(2)}, \ldots, \texttt{init(n)}$ are independent.

Input

The first line of the input contains one integer $n$ ($1\le n\le 10^5$) — the length of the array $r$.

Each of the following $n$ lines contains several integers. The first integer $k_i$ ($0\le k_i\le 10^5$) represents the number of elements in the $i$-th stack, and the following $k_i$ positive integers $c_{i,1},c_{i,2},\ldots,c_{i,k_i}$ ($1\le c_{i,j}\le n$) represent the elements in the $i$-th stack. $c_{i,1}$ is the bottom element.

In each test, $\sum k_i\le 10^6$.

Output

You need to output $n$ values, the $i$-th of which is the value returned by $\texttt{init(i)}$.

Examples
Input
3
3 1 2 2
3 3 1 2
3 1 2 1

Output
1 2 2

Input
5
5 1 2 4 3 4
6 1 2 5 3 3 4
6 1 1 4 4 4 2
9 3 1 4 2 3 5 5 1 2
4 4 4 1 3

Output
1 1 1 1 1

Note

In the first example:

• When you call $\texttt{init(1)}$, set $\texttt{stacks := [[1,2,2],[3,1,2],[1,2,1]]}$, and then call $\texttt{get(stacks, 1)}$.
• $\texttt{stacks[1]}$ is not empty, set $\texttt{new_pos := 2}$, and pop the top element of $\texttt{stacks[1]}$, which makes $\texttt{stacks}$ become $[[1,2],[3,1,2],[1,2,1]]$, and then call $\texttt{get(stacks, 2)}$.
• $\texttt{stacks[2]}$ is not empty, set $\texttt{new_pos := 2}$, and pop the top element of $\texttt{stacks[2]}$, which makes $\texttt{stacks}$ become $[[1,2],[3,1],[1,2,1]]$, and then call $\texttt{get(stacks, 2)}$.
• $\texttt{stacks[2]}$ is not empty, set $\texttt{new_pos := 1}$, and pop the top element of $\texttt{stacks[2]}$, which makes $\texttt{stacks}$ become $[[1,2],[3],[1,2,1]]$, and then call $\texttt{get(stacks, 1)}$.
• $\texttt{stacks[1]}$ is not empty, set $\texttt{new_pos := 2}$, and pop the top element of $\texttt{stacks[1]}$, which makes $\texttt{stacks}$ become $[[1],[3],[1,2,1]]$, and then call $\texttt{get(stacks, 2)}$.
• $\texttt{stacks[2]}$ is not empty, set $\texttt{new_pos := 3}$, and pop the top element of $\texttt{stacks[2]}$, which makes $\texttt{stacks}$ become $[[1],[],[1,2,1]]$, and then call $\texttt{get(stacks, 3)}$.
• $\texttt{stacks[3]}$ is not empty, set $\texttt{new_pos := 1}$, and pop the top element of $\texttt{stacks[3]}$, which makes $\texttt{stacks}$ become $[[1],[],[1,2]]$, and then call $\texttt{get(stacks, 1)}$.
• $\texttt{stacks[1]}$ is not empty, set $\texttt{new_pos := 1}$, and pop the top element of $\texttt{stacks[1]}$, which makes $\texttt{stacks}$ become $[[],[],[1,2]]$, and then call $\texttt{get(stacks, 1)}$.
• $\texttt{stacks[1]}$ is empty, return $1$.
• When you call $\texttt{init(2)}$, set $\texttt{stacks := [[1,2,2],[3,1,2],[1,2,1]]}$, and then call $\texttt{get(stacks, 2)}$.
• $\texttt{stacks[2]}$ is not empty, set $\texttt{new_pos := 2}$, and pop the top element of $\texttt{stacks[2]}$, which makes $\texttt{stacks}$ become $[[1,2,2],[3,1],[1,2,1]]$, and then call $\texttt{get(stacks, 2)}$.
• $\texttt{stacks[2]}$ is not empty, set $\texttt{new_pos := 1}$, and pop the top element of $\texttt{stacks[2]}$, which makes $\texttt{stacks}$ become $[[1,2,2],[3],[1,2,1]]$, and then call $\texttt{get(stacks, 1)}$.
• $\texttt{stacks[1]}$ is not empty, set $\texttt{new_pos := 2}$, and pop the top element of $\texttt{stacks[1]}$, which makes $\texttt{stacks}$ become $[[1,2],[3],[1,2,1]]$, and then call $\texttt{get(stacks, 2)}$.
• $\texttt{stacks[2]}$ is not empty, set $\texttt{new_pos := 3}$, and pop the top element of $\texttt{stacks[2]}$, which makes $\texttt{stacks}$ become $[[1,2],[],[1,2,1]]$, and then call $\texttt{get(stacks, 3)}$.
• $\texttt{stacks[3]}$ is not empty, set $\texttt{new_pos := 1}$, and pop the top element of $\texttt{stacks[3]}$, which makes $\texttt{stacks}$ become $[[1,2],[],[1,2]]$, and then call $\texttt{get(stacks, 1)}$.
• $\texttt{stacks[1]}$ is not empty, set $\texttt{new_pos := 2}$, and pop the top element of $\texttt{stacks[1]}$, which makes $\texttt{stacks}$ become $[[1],[],[1,2]]$, and then call $\texttt{get(stacks, 2)}$.
• $\texttt{stacks[2]}$ is empty, return $2$.
• When you call $\texttt{init(3)}$, set $\texttt{stacks := [[1,2,2],[3,1,2],[1,2,1]]}$, and then call $\texttt{get(stacks, 3)}$.
• $\texttt{stacks[3]}$ is not empty, set $\texttt{new_pos := 1}$, and pop the top element of $\texttt{stacks[3]}$, which makes $\texttt{stacks}$ become $[[1,2,2],[3,1,2],[1,2]]$, and then call $\texttt{get(stacks, 1)}$.
• $\texttt{stacks[1]}$ is not empty, set $\texttt{new_pos := 2}$, and pop the top element of $\texttt{stacks[1]}$, which makes $\texttt{stacks}$ become $[[1,2],[3,1,2],[1,2]]$, and then call $\texttt{get(stacks, 2)}$.
• $\texttt{stacks[2]}$ is not empty, set $\texttt{new_pos := 2}$, and pop the top element of $\texttt{stacks[2]}$, which makes $\texttt{stacks}$ become $[[1,2],[3,1],[1,2]]$, and then call $\texttt{get(stacks, 2)}$.
• $\texttt{stacks[2]}$ is not empty, set $\texttt{new_pos := 1}$, and pop the top element of $\texttt{stacks[2]}$, which makes $\texttt{stacks}$ become $[[1,2],[3],[1,2]]$, and then call $\texttt{get(stacks, 1)}$.
• $\texttt{stacks[1]}$ is not empty, set $\texttt{new_pos := 2}$, and pop the top element of $\texttt{stacks[1]}$, which makes $\texttt{stacks}$ become $[[1],[3],[1,2]]$, and then call $\texttt{get(stacks, 2)}$.
• $\texttt{stacks[2]}$ is not empty, set $\texttt{new_pos := 3}$, and pop the top element of $\texttt{stacks[2]}$, which makes $\texttt{stacks}$ become $[[1],[],[1,2]]$, and then call $\texttt{get(stacks, 3)}$.
• $\texttt{stacks[3]}$ is not empty, set $\texttt{new_pos := 2}$, and pop the top element of $\texttt{stacks[3]}$, which makes $\texttt{stacks}$ become $[[1],[],[1]]$, and then call $\texttt{get(stacks, 2)}$.
• $\texttt{stacks[2]}$ is empty, return $2$.