Codeforces Round 247 (Div. 2) |
---|

Finished |

Virtual contest is a way to take part in past contest, as close as possible to participation on time. It is supported only ICPC mode for virtual contests.
If you've seen these problems, a virtual contest is not for you - solve these problems in the archive.
If you just want to solve some problem from a contest, a virtual contest is not for you - solve this problem in the archive.
Never use someone else's code, read the tutorials or communicate with other person during a virtual contest.

brute force

implementation

*1200

No tag edit access

The problem statement has recently been changed. View the changes.

×
B. Shower Line

time limit per test

1 secondmemory limit per test

256 megabytesinput

standard inputoutput

standard outputMany students live in a dormitory. A dormitory is a whole new world of funny amusements and possibilities but it does have its drawbacks.

There is only one shower and there are multiple students who wish to have a shower in the morning. That's why every morning there is a line of five people in front of the dormitory shower door. As soon as the shower opens, the first person from the line enters the shower. After a while the first person leaves the shower and the next person enters the shower. The process continues until everybody in the line has a shower.

Having a shower takes some time, so the students in the line talk as they wait. At each moment of time the students talk in pairs: the (2*i* - 1)-th man in the line (for the current moment) talks with the (2*i*)-th one.

Let's look at this process in more detail. Let's number the people from 1 to 5. Let's assume that the line initially looks as 23154 (person number 2 stands at the beginning of the line). Then, before the shower opens, 2 talks with 3, 1 talks with 5, 4 doesn't talk with anyone. Then 2 enters the shower. While 2 has a shower, 3 and 1 talk, 5 and 4 talk too. Then, 3 enters the shower. While 3 has a shower, 1 and 5 talk, 4 doesn't talk to anyone. Then 1 enters the shower and while he is there, 5 and 4 talk. Then 5 enters the shower, and then 4 enters the shower.

We know that if students *i* and *j* talk, then the *i*-th student's happiness increases by *g*_{ij} and the *j*-th student's happiness increases by *g*_{ji}. Your task is to find such initial order of students in the line that the total happiness of all students will be maximum in the end. Please note that some pair of students may have a talk several times. In the example above students 1 and 5 talk while they wait for the shower to open and while 3 has a shower.

Input

The input consists of five lines, each line contains five space-separated integers: the *j*-th number in the *i*-th line shows *g*_{ij} (0 ≤ *g*_{ij} ≤ 10^{5}). It is guaranteed that *g*_{ii} = 0 for all *i*.

Assume that the students are numbered from 1 to 5.

Output

Print a single integer — the maximum possible total happiness of the students.

Examples

Input

0 0 0 0 9

0 0 0 0 0

0 0 0 0 0

0 0 0 0 0

7 0 0 0 0

Output

32

Input

0 43 21 18 2

3 0 21 11 65

5 2 0 1 4

54 62 12 0 99

87 64 81 33 0

Output

620

Note

In the first sample, the optimal arrangement of the line is 23154. In this case, the total happiness equals:

Codeforces (c) Copyright 2010-2023 Mike Mirzayanov

The only programming contests Web 2.0 platform

Server time: Jun/05/2023 16:19:13 (l2).

Desktop version, switch to mobile version.

Supported by

User lists

Name |
---|