Virtual contest is a way to take part in past contest, as close as possible to participation on time. It is supported only ICPC mode for virtual contests.
If you've seen these problems, a virtual contest is not for you - solve these problems in the archive.
If you just want to solve some problem from a contest, a virtual contest is not for you - solve this problem in the archive.
Never use someone else's code, read the tutorials or communicate with other person during a virtual contest.

No tag edit access

The problem statement has recently been changed. View the changes.

×
D. New Year and Ancient Prophecy

time limit per test

2.5 secondsmemory limit per test

512 megabytesinput

standard inputoutput

standard outputLimak is a little polar bear. In the snow he found a scroll with the ancient prophecy. Limak doesn't know any ancient languages and thus is unable to understand the prophecy. But he knows digits!

One fragment of the prophecy is a sequence of *n* digits. The first digit isn't zero. Limak thinks that it's a list of some special years. It's hard to see any commas or spaces, so maybe ancient people didn't use them. Now Limak wonders what years are listed there.

Limak assumes three things:

- Years are listed in the strictly increasing order;
- Every year is a positive integer number;
- There are no leading zeros.

Limak is going to consider all possible ways to split a sequence into numbers (years), satisfying the conditions above. He will do it without any help. However, he asked you to tell him the number of ways to do so. Since this number may be very large, you are only asked to calculate it modulo 10^{9} + 7.

Input

The first line of the input contains a single integer *n* (1 ≤ *n* ≤ 5000) — the number of digits.

The second line contains a string of digits and has length equal to *n*. It's guaranteed that the first digit is not '0'.

Output

Print the number of ways to correctly split the given sequence modulo 10^{9} + 7.

Examples

Input

6

123434

Output

8

Input

8

20152016

Output

4

Note

In the first sample there are 8 ways to split the sequence:

- "123434" = "123434" (maybe the given sequence is just one big number)
- "123434" = "1" + "23434"
- "123434" = "12" + "3434"
- "123434" = "123" + "434"
- "123434" = "1" + "23" + "434"
- "123434" = "1" + "2" + "3434"
- "123434" = "1" + "2" + "3" + "434"
- "123434" = "1" + "2" + "3" + "4" + "34"

Note that we don't count a split "123434" = "12" + "34" + "34" because numbers have to be strictly increasing.

In the second sample there are 4 ways:

- "20152016" = "20152016"
- "20152016" = "20" + "152016"
- "20152016" = "201" + "52016"
- "20152016" = "2015" + "2016"

Codeforces (c) Copyright 2010-2023 Mike Mirzayanov

The only programming contests Web 2.0 platform

Server time: Jan/27/2023 11:05:14 (k3).

Desktop version, switch to mobile version.

Supported by

User lists

Name |
---|