Virtual contest is a way to take part in past contest, as close as possible to participation on time. It is supported only ICPC mode for virtual contests.
If you've seen these problems, a virtual contest is not for you - solve these problems in the archive.
If you just want to solve some problem from a contest, a virtual contest is not for you - solve this problem in the archive.
Never use someone else's code, read the tutorials or communicate with other person during a virtual contest.

No tag edit access

E. Complete the Permutations

time limit per test

5 secondsmemory limit per test

256 megabytesinput

standard inputoutput

standard outputZS the Coder is given two permutations *p* and *q* of {1, 2, ..., *n*}, but some of their elements are replaced with 0. The distance between two permutations *p* and *q* is defined as the minimum number of moves required to turn *p* into *q*. A move consists of swapping exactly 2 elements of *p*.

ZS the Coder wants to determine the number of ways to replace the zeros with positive integers from the set {1, 2, ..., *n*} such that *p* and *q* are permutations of {1, 2, ..., *n*} and the distance between *p* and *q* is exactly *k*.

ZS the Coder wants to find the answer for all 0 ≤ *k* ≤ *n* - 1. Can you help him?

Input

The first line of the input contains a single integer *n* (1 ≤ *n* ≤ 250) — the number of elements in the permutations.

The second line contains *n* integers, *p*_{1}, *p*_{2}, ..., *p*_{n} (0 ≤ *p*_{i} ≤ *n*) — the permutation *p*. It is guaranteed that there is at least one way to replace zeros such that *p* is a permutation of {1, 2, ..., *n*}.

The third line contains *n* integers, *q*_{1}, *q*_{2}, ..., *q*_{n} (0 ≤ *q*_{i} ≤ *n*) — the permutation *q*. It is guaranteed that there is at least one way to replace zeros such that *q* is a permutation of {1, 2, ..., *n*}.

Output

Print *n* integers, *i*-th of them should denote the answer for *k* = *i* - 1. Since the answer may be quite large, and ZS the Coder loves weird primes, print them modulo 998244353 = 2^{23}·7·17 + 1, which is a prime.

Examples

Input

3

1 0 0

0 2 0

Output

1 2 1

Input

4

1 0 0 3

0 0 0 4

Output

0 2 6 4

Input

6

1 3 2 5 4 6

6 4 5 1 0 0

Output

0 0 0 0 1 1

Input

4

1 2 3 4

2 3 4 1

Output

0 0 0 1

Note

In the first sample case, there is the only way to replace zeros so that it takes 0 swaps to convert *p* into *q*, namely *p* = (1, 2, 3), *q* = (1, 2, 3).

There are two ways to replace zeros so that it takes 1 swap to turn *p* into *q*. One of these ways is *p* = (1, 2, 3), *q* = (3, 2, 1), then swapping 1 and 3 from *p* transform it into *q*. The other way is *p* = (1, 3, 2), *q* = (1, 2, 3). Swapping 2 and 3 works in this case.

Finally, there is one way to replace zeros so that it takes 2 swaps to turn *p* into *q*, namely *p* = (1, 3, 2), *q* = (3, 2, 1). Then, we can transform *p* into *q* like following: .

Codeforces (c) Copyright 2010-2019 Mike Mirzayanov

The only programming contests Web 2.0 platform

Server time: Oct/20/2019 10:47:07 (f2).

Desktop version, switch to mobile version.

Supported by

User lists

Name |
---|