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Codeforces Round 404 (Div. 2) |
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A. Anton and Polyhedrons

time limit per test

2 secondsmemory limit per test

256 megabytesinput

standard inputoutput

standard outputAnton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:

- Tetrahedron. Tetrahedron has 4 triangular faces.
- Cube. Cube has 6 square faces.
- Octahedron. Octahedron has 8 triangular faces.
- Dodecahedron. Dodecahedron has 12 pentagonal faces.
- Icosahedron. Icosahedron has 20 triangular faces.

All five kinds of polyhedrons are shown on the picture below:

Anton has a collection of *n* polyhedrons. One day he decided to know, how many faces his polyhedrons have in total. Help Anton and find this number!

Input

The first line of the input contains a single integer *n* (1 ≤ *n* ≤ 200 000) — the number of polyhedrons in Anton's collection.

Each of the following *n* lines of the input contains a string *s*_{i} — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:

- "Tetrahedron" (without quotes), if the
*i*-th polyhedron in Anton's collection is a tetrahedron. - "Cube" (without quotes), if the
*i*-th polyhedron in Anton's collection is a cube. - "Octahedron" (without quotes), if the
*i*-th polyhedron in Anton's collection is an octahedron. - "Dodecahedron" (without quotes), if the
*i*-th polyhedron in Anton's collection is a dodecahedron. - "Icosahedron" (without quotes), if the
*i*-th polyhedron in Anton's collection is an icosahedron.

Output

Output one number — the total number of faces in all the polyhedrons in Anton's collection.

Examples

Input

4

Icosahedron

Cube

Tetrahedron

Dodecahedron

Output

42

Input

3

Dodecahedron

Octahedron

Octahedron

Output

28

Note

In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces.

Codeforces (c) Copyright 2010-2023 Mike Mirzayanov

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