UVA 11762
Difference between en1 and en2, changed 4 character(s)
[UVA](https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2862) 11762↵
  ↵
Suppose we want to calculate E(N) where N is a number,k is the number of it’s distinct prime factors and p is the number of primes < n↵
Normal rule, E(N)=(1/p)*(
1 + E(N/a1) + E(N/a2) + E(N/a3) … + E(N/ak)) + ((p-k)/p)*(1 + E(N))↵

I don't understand the editorial part of this problem....↵
Below part is the editorial part..↵

E(N)=1+(1/p)*(E(N/a1) + E(N/a2) + E(N/a3) … + E(N/ak)) + ((p-k)/p) * E(N)↵

-Why here add 1 in the first? Why not add 1 in the failure part?

History

 
 
 
 
Revisions
 
 
  Rev. Lang. By When Δ Comment
en4 English Upgrading..... 2019-02-05 11:10:29 2 Tiny change: 'imes < n\nNormal ' -> 'imes < n\n\nNormal '
en3 English Upgrading..... 2019-02-05 11:10:12 225
en2 English Upgrading..... 2019-02-05 11:03:58 4 Tiny change: 'N)=(1/p)*(E(N/a1) + ' -> 'N)=(1/p)*(1 + E(N/a1) + '
en1 English Upgrading..... 2019-02-05 03:52:11 594 Initial revision (published)